1 The Asp residue with a pka = 6 is found in the active site of an enzyme. This residue acts as anacid catalyst. Assuming that the enzyme is stable at a wide range of PH and that the Aspartic acidresidue is the only ionizable residue in the active site, please draw the curve of enzyme activityversus pH on the graph below and explain the shape of your curve. (10 points)100% enzyme activity7550253LO57pHT911

Enzymes are biochemical catalysts that increase the rate of biological reactions. Most enzymes are…

Answered: 1 The Asp residue with a pka = 6 is…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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L(24 points) Explain How is the Michaelis constant defined. and what does a low or high value for Km tell you? What is the difference between the velocity and initial velocity of an enzyme reaction? What determines the efficiency of an enzyme reaction, and what terms are used to describe it? 2. (50 points) About how to obtain kinetic data experimentally Lisa decides to obtain values for the Km and Vmax of an enzyme she has just isolated from liver cells (it is now pure), using a Michaelis Menten plot. Describe in detail what kinds of measurements she would have to make, and what she would need to plot on graphs in order to estimnte the values for Km and Vmax. (Show the kinds of graphs she would have to plot, and how these will allow her to estimate Km and Vmax.) Describe how she would be able to obtain Vmax experimentally and from the Michaelis Menten plot - what conditions are needed and what would be measured). Also, describe what she would have to do to obtain the turnover number of…
A generalized enzyme active site is shaped like a hemisphere with a radius of 45Å. The active site holds the following amino acids in a homeostatic solution (pH = 7.38): -HAVARILKHAVARILKHAVARILK- Assuming the charge is distributed uniformly along the hemisphere, determine the force at which this active site acts upon a single ATP molecule at the center of the hemisphere.
You are working on an enzyme that obeys standard Michaelis-Menten kinetics. What variable is the V, dependant on if the concentration of the substrate is substantially higher than the concentration of the enzyme? [S] [E] [ES] O [P] O not enough information provided
5.50 1/V, min/umol 5.00 4.50 4.00 y = 0.9474x + 2.6649 y = 0.9997x + 2.032 0.00 1.00 2.00 2.50 3.00 1/[S], uM -1 Looking at the double reciprocal plot for an enzyme in the absence of inhibitor and in the presence of two concentrations of inhibitor, what would be the Vmax for the uninhibited enzyme? (bottom graph) Equation is given. Choose the one best answer. 3.50 3.00 2.50 2.00
The steady-state kinetics of an enzyme are studied in the absence and presence of an inhibitor (inhibitor A). The initial rate is given as a function of substrate concentration in the following table: v[(mmol/L)min- [S] (mmol/L) No inhibitor Inhibitor A 1.25 1.72 0.98 1.67 2.04 1.17 2.50 2.63 1.47 5.00 3.33 1.96 10.00 4.17 2.38 (a) What kind of inhibition (competitive, uncompetitive, or mixed) is involved? (b) Determine Vmax and Ky in the absence and presence of inhibitor.
The initial rates of an enzyme-catalyzed reaction have been determined for five different [S] (see table below). [S]o (mol.L-¹) 1.0 x 10 1.5 x 10-4 2.0 x 10-4 -4 5.0 x 10 7.5 x 10-4 -1 Vo (μmol.L-¹ min-¹) 28 35 42 63 75 1- Determine graphically the value of Km (first with the Michaelis-Menten representation and then with the Lineweaver-Burk representation, then compare by reporting on the Michaelis-Menten representation the values found by the Lineweaver-Burk representation) 2- Calculate the concentration of a competitive inhibitor 1, with a K₁ value of 2.4.104 M, whose action would quadruple the apparent value of Km.
The turnover number for an enzyme is known to be 5000min-1. Given the following set of data, Substrate concentration(mM) 1, 2, 4, 6, 100, 1,000 Initial Rate(micromol/min) 167, 250, 334, 376, 498, 499 a) What is the Km of the enzyme for the substrate? (do this without using a calculator) b) What is the total amount of enzyme present in the assay?
3. (a) The beakers below represent different conditions for measuring the initial velocity (vo) of an enzyme-catalyzed reaction under the steady-state approximation. The gray "donut-shaped" struc- tures represent the enzyme. The blue, filled circles represent free substrate molecules. The red cir- cles represent substrate molecules bound in the active site of the enzyme forming the Michaelis (ES) complex. Indicate in the diagram of the double reciprocal plot which kinetic parameters or variables each of the three "beaker conditions" represent either alone or in combination with another. A B 455 C V₁™¹ [So]-¹
. The optimal conditions for salivary lysozyme (hydrolyzing glycoproteins of bacterial wall) are 37 C - temperature and pH is 5.2. Explain the decrease in this enzyme activity if the temperature will rise up to 60 °C and pH will be changed to 8.0. To answer the question: a) draw the graph of the velocity dependency on temperature and pH; b) calculate the relative enzyme activity if 10 mg of lysozyme catalyzes the formation of 5 uM of the product per 2 minutes. Concidor NH3: 5.
The following data was obtained during kinetic analysis of an enzyme with and without an inhibitor. Substrate concentration (mM) Reaction rate without inhibitor (µM/s) Reaction rate with inhibitor (µM/s) 10 28 12 20 50 23 40 83 42 60 107 58 100 139 83 200 179 125 300 197 150 400 209 167 560 227 197 How do you calculate the KM for the enzyme in the absence of an inhibitor. And how do you calculate kcat with the given enzymatic concentration of 5 µM.
An enzyme catalyzes a reaction with a K of 7.50 mM and a Vmax of 4.15 mMs. Calculate the reaction velocity, o, for each substrate concentration. [S] = 1.75 mM MM-s-1 [S] = 7.50 mM [S] = 11.0 mM DO mM-s mM-s
Draw the isomers for each aldotetrose and ketopentose in the figure below and designate each isomer as a D or L sugar and designate also the R and S in every chiral centers. Label the enantiomers and diastereomers respectively. CH,OH C=0 Н-С—ОН Н-С—ОН Н-С —ОН Н-С—ОН ČH,OH ČH,OH

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