BIOCHEMISTRY QUESTIONThe initial rate (VO) data as a function of substrate concentration [S] for an enzyme (Enzyme1) thatobeys Michaelis-Menten kinetics are shown in the table below. The totalenzyme concentration is 2.5 nM.[S](μm)16.08.04.02.01.0v (μMsec ¹)48.532.719.811.15.88(a) Calculate KM for the enzyme, using the estimated slope (slope = (y2-y1)/(x2-x1)) from aLineweaver-Burk plot. Show your work and don't forget the units!(b) When the enzyme concentration is 2.5 nM, a Lineweaver-Burk plot of this data gives a line with a y-intercept of 0.0106 μ M-1 sec. Calculate kcat for the enzyme. (Show yourwork and don't forget to include units).(c) A second enzyme (Enzyme2) also obeys Michaelis-Menten kinetics. Its kcat and KM are 800 sec-1and 5 µM, respectively. Which is the more efficient enzyme? Briefly explaind) Is Enzyme 1 diffusion limited? Explain.

Enzymes kinetics - is the study of the reaction rate of enzyme catalyzed reactions. The reaction…

Answered: The initial rate (v0) data as a…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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An enzyme-catalyzed reaction has a KM of 20.0 mmol L-1 and Vmax of 17.0 pmol s-1. When a mixed inhibitor is added, the apparent KM is 50.0 mmol L-1 and the apparent Vmax is 5.20 pmol s-1. Calculate α.
For a Michaelis-Menten reaction, k₁=5 x 107/M-s, k-1-2 x 104/s, and k2=4 x 10²/s. Calculate the Ks and KM for this reaction. Does substrate binding achieve equilibrium or steady state?
The KM values for the reaction of chymotrypsin with two different substrates are given in the table below. Considering this information, which substrate has the lower apparent affinity for the enzyme? Which substrate is likely to give a lower value for Vmax? Substrate N-acetylvaline ethyl ester N-acetyltyrosine ethyl ester KM (M) 8.8 X 10-² 6.6 X 10-4 N-acetylvaline ethyl ester has the lower apparent affinity for the enzyme; it will also likely to give a lower Vmax: N-acetyltyrosine ethyl ester has the lower apparent affinity for the enzyme; it will also likely to give the lower V₁ max. N-acetylvaline ethyl ester has the lower apparent affinity for the enzyme; N- acetyltyrosine ethyl ester is likely to give the lower Vmax: N-acetyltyrosine ethyl ester has the lower apparent affinity for the enzyme; N- acetylvaline will likely to give the lower Vmax. None of the above statements are correct.
The Michaelis-Menten rate equation for reversible mixed inhibition is written as Vo = Vmax [S] aKm + a' [S] where Vo is initial velocity, Vmax is maximum velocity, [S] is substrate concentration, a represents the effect of the inhibitor bound to free enzyme (E), a' represents the effect of the inhibitor bound to the enzyme-substrate complex (ES), and Km is the Michaelis constant that represents the [S] at which the reaction reaches/Vm Vmax 2α' Derive an expression for the effect of a reversible inhibitor on apparent Km from the previous equation. Use the alphabet tab to enter a and the basic tab to enter the prime sign in your answer. = Apparent, or observed, Km is equivalent to the [S] at which Vo max. apparent Km =
The enzyme, fumarate, has the following kinetic constants: k 1 k 2 k -1 where k 1 = 10 9 M -1 s -1 k -1 =4.4 x 10 4 s -1 k 2 = 10 3 s -1 a. What is the value of the Michaelis constant for this enzyme? b. At an enzyme concentration of 10 -6 M, what will be the initial rate of product"
In gluconeogenesis, only the carbon skeletons of amino acids, not fatty acids, are utilised. So how does fatty acid oxidation in the liver produce brain fuel? Describe the substances and routes involved.
If you want to determine the KM for lactate, what protocol do you set up? Discuss the significance of the following kinetic parameters that are used to characterize enzyme activity: KM, Vmax, kcat, and kcat / KM.

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The initial rate (v0) data as a function of substrate concentration [S] for an enzyme (Enzyme1) that obeys Michaelis-Menten kinetics are shown in the table below. The total enzyme concentration is 2.5 nM.