. Each of the following compounds can be prepared by a mixed aldol condensation reaction. Give the Cructures of the aldehyde and/or ketone precursors for each aldol product and formulate the reaction. 0 CH=CHCCH 3. Ph 1
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- 2 Moin H3C H H₂C C⇒x= base :0: OH Hori H3C H. The aldol reaction is a carbonyl condensation reaction between two carbonyl partners and involves a combination of nucleophilic addition and a-substitution steps. One partner is converted into an enolate ion nucleophile and adds to the electrophilic carbonyl group of the second partner. In the classic aldol reaction, the carbonyl partners are aldehydes or ketones, although aldehydes are more reactive. The product is a B-hydroxy carbonyl compound. Under reaction conditions slightly more vigorous than those employed for the aldol reaction, the ß-hydroxyl group is eliminated in an E1cB dehydration to give an a,ß-unsaturated carbonyl compound. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions H₂C Ἡ :0: heat H Home H3C + H₂ODraw the structure of the hydroxyaldehyde product from the self-aldol reaction of each of the following aldehydes: (a) propanal; (b) phenylethanal; (c) 3-phenylpropanal; (d) benzaldehyde.base 2 H3C H H3C OH heat H H3C + H₂O H The aldol reaction is a carbonyl condensation reaction between two carbonyl partners and involves a combination of nucleophilic addition and a-substitution steps. One partner is converted into an enolate ion nucleophile and adds to the electrophilic carbonyl group of the second partner. In the classic aldol reaction, the carbonyl partners are aldehydes or ketones, although aldehydes are more reactive. The product is a ẞ-hydroxy carbonyl compound. Under reaction conditions slightly more vigorous than those employed for the aldol reaction, the ẞ-hydroxyl group is eliminated in an E1CB dehydration to give an a,ẞ-unsaturated carbonyl compound. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions X :OH H₂O: а کی H₂C H H₂C H H
- H3C OH OH H+ CH3 Esters can be synthesized by an acid-catalyzed nucleophilic acyl substitution between an alcohol and a carboxylic acid; this process is called the Fischer esterification reaction. Because the alcohol oxygen is a poor nucleophile, the carbonyl carbon is made a better electrophile by protonation of the carbonyl oxygen. The steps of the synthesis are all reversible. The reaction is generally driven to completion by using an excess of the liquid alcohol as a solvent, or by distilling off the product as it forms. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions CIX 10-4 H₂O CH3 H₂O CH3The Stork reaction is a condensation reaction between an enamine donor and an α,β-unsaturated carbonyl acceptor. The overall reaction consists of a three-step sequence of formation of an enamine from a ketone, Michael addition to an α,β-unsaturated carbonyl compound, and hydrolysis of the enamine in dilute acid to regenerate the ketone. Consider the Stork reaction between cyclohexanone and propenal Draw the structure of the product of the enamine formed between cyclohexanone and dimethylamine. - Michael addition to an α,β-unsaturated carbonyl compound, and - hydrolysis of the enamine in dilute acid to regenerate the ketone.I H H3C NOC XT :0: MET H₂C base H3C The aldol reaction is a carbonyl condensation reaction between two carbonyl partners and involves a combination of nucleophilic addition and a-substitution steps. One partner is converted into an enolate ion nucleophile and adds to the electrophilic carbonyl group of the second partner. In the classic aldol reaction, the carbonyl partners are aldehydes or ketones, although aldehydes are more reactive. The product is a ß-hydroxy carbonyl compound. H OH q H3C H₂C H Under reaction conditions slightly more vigorous than those employed for the aldol reaction, the ß-hydroxyl group is eliminated in an E1cB dehydration to give an a,ß-unsaturated carbonyl compound. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions heat H H + H₂O
- H3C. H3C. CH3 nnc» XT :OH 2 CH₂OH HCI catalyst Aldehydes and ketones react reversibly with two equivalents of alcohol in the presence of an acid catalyst to give acetals. Alcohols are poor nucleophiles, and so protonation of the carbonyl oxygen is used to make the carbonyl carbon a stronger electrophile. Addition of the first equivalent of alcohol gives a hemiacetal, a hydroxyether. Addition of the second equivalent of alcohol is accompanied by loss of water to yield the product acetal. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions CH3 H3C CH3OH H3CQ OCH3 CH3 H3C. H HO: :OCH 3 CH3 46A synthetic organic molecule, G, which contains both aldehyde and ether functional groups, is subjected to a series of reactions in a multi-step synthesis pathway. In the first step, G undergoes a Wittig reaction, leading to the formation of an alkene, H. Subsequently, H is treated with an ozone (O3) reagent followed by a reducing agent in an ozonolysis reaction, resulting in the formation of two different products, I and J. Considering the functional groups present in G and the nature of the reactions involved, what are the most probable structures or functional groups present in products I and J? A. I contains a carboxylic acid group, and J contains an aldehyde group. B. I contains a ketone group, and J contains an alcohol group. C. I and J both contain aldehyde groups. D. I contains an ester group, and J contains a ketone group. Don't use chat gpt.base H3C H OH heat H + H₂O H The aldol reaction is a carbonyl condensation reaction between two carbonyl partners and involves a combination of nucleophilic addition and a-substitution steps. One partner is converted into an enolate ion nucleophile and adds to the electrophilic carbonyl group of the second partner. In the classic aldol reaction, the carbonyl partners are aldehydes or ketones, although aldehydes are more reactive. The product is a ẞ-hydroxy carbonyl compound. In the mixed aldol reaction, the best results are obtained when one of the partners does not have an a-hydrogen. It cannot form an enolate anion and can therefore not undergo self-reaction. The enolizable aldehyde is added slowly to a basic solution of the first aldehyde so that the mixed product is preferentially formed. Under reaction conditions slightly more vigorous than those employed for the aldol reaction, the ẞ-hydroxyl group is eliminated in an E1cB dehydration to give an a,ß-unsaturated carbonyl compound.…
- Use the Witting reaction to answer the following question.The acetoacetic ester synthesis is a carbonyl alkylation reaction. It is used to prepare methyl ketones from primary alkyl halides, lengthening the carbon chain by three atoms. Thus, the product can be visualized as being a "substituted acetone." The reaction consists of three steps: generation of the enolate anion followed by SN2 reaction with a primary alkyl halide, ester hydrolysis under acid conditions, and decarboxylation. м Br H3C H3C OEt 1. NaOEt 2. H₂O* 3. heat H₂C. Draw curved arrows to show the movement of electrons in this step of the mechanism. CO₂ EtOH CH3 Arrow-pushing Instructions H3C 1:0: :0: :Br: Br: H₂C CH3 CH3 H3C CH3 7bThe acetoacetic ester synthesis is a carbonyl alkylation reaction. It is used to prepare methyl ketones from primary alkyl halides, lengthening the carbon chain by three atoms. Thus, the product can be visualized as being a "substituted acetone." The reaction consists of three steps: generation of the enolate anion followed by SN2 reaction with a primary alkyl halide, ester hydrolysis under acid conditions, and decarboxylation. Br H₂C H3C 1. NaOEt 2. H₂O* 3. heat H₂C. OEt Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions H X CO2 CH3 + EtOH :OH На CH3 CO2 CH3 CH3 CH3



