Lab 3

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University of Texas *

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Mechanical Engineering

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Dec 6, 2023

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Neha Karne Lab 3 Part 1 1. Critically damped → α = ω 0 α = R/2L = R/(2*0.00047) = R/0.00094 ω 0 = 1/ = 1/ = 1458649.91 𝐿𝐶 0. 00047 * 10 −9 R/0.00094 = 1458649.91498 R = 1371.13 Ω 2. α = R/2L = 2000/(2*0.00047) = 2127659.57 ω 0 = 1458649.91 α > ω 0 overdamped 3. α = R/2L = 510/(2*0.00047) = 542553.191 ω 0 = 1458649.91 α < ω 0 underdamped 4. α = R/2L = 2000/(2*0.00047) = 106382.979 ω 0 = 1458649.91 α < ω 0 underdamped Part 2 6. Is the behavior of the capacitor voltage consistent with the damping? YES 7. Make a sketch of the result on the oscilloscope and have the TA initial it. Does it match the damping that you predicted in question 2? Yes, it is overdamped.
9. Is the behavior of the capacitor voltage consistent with the damping? YES 10. Make a sketch of the result on the oscilloscope and have the TA initial it. Does it match the damping that you predicted in question 3? Yes, it is underdamped.
12. Is the behavior of the capacitor voltage consistent with the damping? YES 13. Make a sketch of the result on the oscilloscope and have the TA initial it. Does it match the damping that you predicted in question 4? Yes, it is underdamped. 14. Is the behavior of the inductor current consistent with the damping? NO because when the capacitor is fully charged it acts like an open circuit leading the current to zero.
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