The 8kg body is moved to the right of the equilibrium position and released from rest at time t = 0. The viscous damping coefficient is 23NS/mand the spring stiffness, K is 38N/m. Determine the damping factor (ratio) of the system.Note: Give your answer to 3 decimal places.Other Parameters:Logarithmic Decrement (8):Answer:2ng2T C8 = In = In1 = 5 wnTd = 5wnX2Xn+11-5wa 2mkDamping Ratio (5): 5=2vkm2mnV(21)2+8Frequency of damped vibration (wa): wa =1-WnUndamped Forced Vibration:Frequency Ratio (): r-Xp-x sin w tNext pageHous pageType here to search stiffness, K is 38N/m. Determine the damping factor (ratio) of the system.r answer to 3 decimal places.Other Parameters:Logarithmic Decrement (õ):Answer:2m2m. C8 = InnIn1 = ( WnTd@12mXn+11-5Damping Ratio (5): 5 =-v(2m)+62Ce 2ykm2m@nFrequency of damped vibration (wa); wa =Undamped Forced Vibration:Fo/kXp=x sin w t1-)Frequency Ratio (r): r =wnII

Given : m=8 kgc=23 Ns/mk=38 N/m

The 8kg body is moved to the right of the equilibrium position and released from rest at time t = 0. The viscous damping coefficient is 23NS/m and the spring stiffness, K is 38N/m. Determine the damping factor (ratio) of the system. Note: Give your answer to 3 decimal places. Other Parameters: C Logarithmic Decrement (6): Answer: 2ng 2n c 2n 8 = In = 1 In wnTa = 5wn %3D %3D wa 2m X2 Xn+1 !! Damping Ratio (5): 5 = %3D k J(2m)+8 2vkm 2mn Frequency of damped vibration (wa): wa-

The 8kg body is moved to the right of the equilibrium position and released from rest at time t = 0. The viscous damping coefficient is 23NS/m and the spring stiffness, K is 38N/m. Determine the damping factor (ratio) of the system. Note: Give your answer to 3 decimal places. Other Parameters: C Logarithmic Decrement (6): Answer: 2ng 2n c 2n 8 = In = 1 In wnTa = 5wn %3D %3D wa 2m X2 Xn+1 !! Damping Ratio (5): 5 = %3D k J(2m)+8 2vkm 2mn Frequency of damped vibration (wa): wa-

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Free Damped Vibrations

Free vibration is a type of vibration in which the external force is removed after giving the initial displacement to a body/system. In other words, in this type of vibration, force is applied at the initial displacement of the system, and after the initial displacement, force is removed, and the system vibrates at the natural frequency.

Question

The 8kg body is moved to the right of the equilibrium position and released from rest at time t = 0. The viscous damping coefficient is 23NS/m
and the spring stiffness, K is 38N/m. Determine the damping factor (ratio) of the system.
Note: Give your answer to 3 decimal places.
Other Parameters:
Logarithmic Decrement (8):
Answer:
2ng
2T C
8 = In = In1 = 5 wnTd = 5wn
X2
Xn+1
1-5
wa 2m
k
Damping Ratio (5): 5=
2vkm
2mn
V(21)2+8
Frequency of damped vibration (wa): wa =
1-Wn
Undamped Forced Vibration:
Frequency Ratio (): r-
Xp-x sin w t
Next page
Hous page
Type here to search

stiffness, K is 38N/m. Determine the damping factor (ratio) of the system.
r answer to 3 decimal places.
Other Parameters:
Logarithmic Decrement (õ):
Answer:
2m
2m. C
8 = In
n
In
1 = ( WnTd
@12m
Xn+1
1-5
Damping Ratio (5): 5 =-
v(2m)+62
Ce 2ykm
2m@n
Frequency of damped vibration (wa); wa =
Undamped Forced Vibration:
Fo/k
Xp=x sin w t
1-)
Frequency Ratio (r): r =
wn
II

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