The 8kg body is moved to the right of the equilibrium position and released from rest at time t = 0. The viscous damping coefficient is 23NS/mand the spring stiffness, K is 38N/m. Determine the damping factor (ratio) of the system.Note: Give your answer to 3 decimal places.Other Parameters:Logarithmic Decrement (8):Answer:2ng2T C8 = In = In1 = 5 wnTd = 5wnX2Xn+11-5wa 2mkDamping Ratio (5): 5=2vkm2mnV(21)2+8Frequency of damped vibration (wa): wa =1-WnUndamped Forced Vibration:Frequency Ratio (): r-Xp-x sin w tNext pageHous pageType here to search stiffness, K is 38N/m. Determine the damping factor (ratio) of the system.r answer to 3 decimal places.Other Parameters:Logarithmic Decrement (õ):Answer:2m2m. C8 = InnIn1 = ( WnTd@12mXn+11-5Damping Ratio (5): 5 =-v(2m)+62Ce 2ykm2m@nFrequency of damped vibration (wa); wa =Undamped Forced Vibration:Fo/kXp=x sin w t1-)Frequency Ratio (r): r =wnII

Given : m=8 kgc=23 Ns/mk=38 N/m

The 8kg body is moved to the right of the equilibrium position and released from rest at time t = 0. The viscous damping coefficient is 23NS/m and the spring stiffness, K is 38N/m. Determine the damping factor (ratio) of the system. Note: Give your answer to 3 decimal places. Other Parameters: C Logarithmic Decrement (6): Answer: 2ng 2n c 2n 8 = In = 1 In wnTa = 5wn %3D %3D wa 2m X2 Xn+1 !! Damping Ratio (5): 5 = %3D k J(2m)+8 2vkm 2mn Frequency of damped vibration (wa): wa-

The 8kg body is moved to the right of the equilibrium position and released from rest at time t = 0. The viscous damping coefficient is 23NS/m and the spring stiffness, K is 38N/m. Determine the damping factor (ratio) of the system. Note: Give your answer to 3 decimal places. Other Parameters: C Logarithmic Decrement (6): Answer: 2ng 2n c 2n 8 = In = 1 In wnTa = 5wn %3D %3D wa 2m X2 Xn+1 !! Damping Ratio (5): 5 = %3D k J(2m)+8 2vkm 2mn Frequency of damped vibration (wa): wa-

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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The mass of the system shown below is 10Kg. The mass is initially at rest when at time t=0, it is given an initial disturbance as shown. The viscous damping coefficient is 100NS/m and the spring stiffness, K is 100N/m. Which equation describes the movement of the mass. Disturbance Mass Spring Damper Select one: x(t) = (A, + A½t) e¯wnt a. %3D x(t) = A, e(-3+v?-1)wnt + A,e(-3-v?-1 )wnt x = (A3cos wat+ A4sin wat)e-wnt %3D C. Finish attempt.. evious page
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