Andrew Li 101258492 Fe short report, TA-Maram Bakiro, 11-03-22 (1)
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Spectrophotometric determination of iron
Date submitted: 11-03-2022
By:
Andrew Li (101258492)
Lab section:L4
TA:
Maram Bakiro
Procedure:
1.
You’ll be given a CONCENTRATED STANDARD IRON solution that contains 0.2500 g/L
of iron. Pipette 25.00ml of this into a 500.00ml volumetric flask and dilute up to the mark
with distilled water. Mix well as you fill the volumetric flask. This is your DILUTE
STANDARD IRON solution.
2.
Prepare a set of six calibration standards using this DILUTED STANDARD IRON
SOLUTION, containing the following total amounts of iron: 0.00 mg (the “blank” with no
iron in it), 0.05 mg, 0.10 mg, 0.15 mg, 0.20 mg, 0.25 mg.NOTE: do NOT fill these six
flasks to their marks. Set them aside for now. These are your calibration standards.
3.
Obtain an unknown iron sample and note the sample number. Pipette 10.00 ml of your
unknown iron sample into a 250.00 ml volumetric flask and dilute it to the mark with
distilled water. Mix it properly as described in step 1.
4.
Pipette two 25.00 ml aliquots of this solution into two individual 50.00 ml volumetric
flasks. Note the dilution factor for these solutions relative to the original unknown. This
value will be needed to calculate the original concentration of iron in the unknown (which
is the objective of this lab.)
5.
You now have eight 50 ml volumetric flasks: your blank, five flasks with increasing
amounts of your standard iron solution in them, and two with samples of your unknown
solution. Add to each one, by pipette:4.0 ml 10% hydroxylamine hydrochloride 4.0 ml
0.3% ortho-phenanthroline
6.
Swirl each and allow them to sit for at least 10 minutes.
7.
After 10 minutes have passed, dilute each flask to the mark with distilled water, using
proper technique (as in step 1).
8.
Set the wavelength on the spectrophotometer to the value you chose based on the
spectrum of the iron(II) ortho-phenanthroline complex. ONCE YOU SET IT, DO NOT
CHANGE THIS WAVELENGTH DURING THE LAB.
9.
Fill a cuvette about 2/3 full of your blank solution and run the blank in the
spectrophotometer to zero it.
10. Empty the blank solution out of the cuvette and rinse it with your most dilute solution. Fill
the cuvette about 2/3 full and measure the absorbance.
11. Empty this solution, and rinse with the next one in order of increasing concentration. Fill
it 2/3 full with this second solution, and measure the absorbance.
12. Repeat this step for each of the calibration solutions, going up in concentration from
least to most concentration. Make sure each absorption is recorded.
13. Rinse the cuvette with distilled water, and then rinse with a small amount of your first
unknown solution. Measure the absorption of your first unknown. Rinse the cuvette with
a small amount of your second unknown solution, then fill it and measure the absorption
of your second unknown.
Data:
Iron amount (mg)
Absorption
0.00
-0.022
0.05
0.154
0.10
0.352
0.15
0.540
0.20
0.739
0.25
0.937
Unknown 1
0.651
Unknown 2
0.646
Table 1. Absorptions of different concentration of diluted iron
Calculations:
1.
Graph 1- Concentration(mg/50ml) vs Absorbance (excluding unknown samples)
2.
Beer-lambert’s Law: A=
εlc
l=1 cm (cuvette)
Equation of the line: y=mx+b
y=absorption value
x= concentration
Unknown #1
y=3.85x-0.0313
0.651=3.85x-0.0313
0.6823=3.85x
x=0.1772207792
x=0.177mg/50mL or 0.00354mg/mL
Unknown #2
0.646=3.85x-0.0313
x=0.1759220779
x=0.176mg/50mL or 0.00352mg/mL
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3.
Unknown sample
Amount of iron in the undiluted= (0.00354+0.00352)/2
=0.00353mg/ml= 0.00353g/L
0.00353 g/L x 50(Dilution factor)= 0.1765g/L=0.177g/L
Amount of iron in undiluted is 0.177g/L
4.
Relative spread=((higher value-lower value)/average value)x1000
Relative spread=((0.00354-0.00352)/0.00353)x1000
Relative spread= 5.67 ppt
5.
Accepted value of unknown iron sample= 0.1735g/L
Relative error= ((Calculated Result-Accepted Result)/Accepted Result)x 100%
Relative error= ((0.1765-0.1735)/0.1735)x100%
Relative error = 1.72910663
Relative error=1.73%
6.
Slope of the curve is : 3.85
m=A=
εl
ε=m/l
ε=3.85/1
ε=3.85L/mol*cm
Results:
The concentration 1.73% higher than the accepted value of the unknown iron
sample, of 0.1735 g/L. The margin for error is very low, and some possibilities of errors
come from slight smudges on the cuvette causing some added absorption of light. It
also could be the account that the measuring equipment all have margins of error, and
that slight error caused a slight increase in measured concentration of iron.
Conclusion:
The results of the experiments show that the amount of measured iron in the
unknown sample was 0.177 g/L. That measured value was 1.73% higher than the
accepted value, and the spread of data was 5.67 ppt. The extinction coefficient is 3.85
L/mol*cm.
References
Carleton University, Fe: SPECTROPHOTOMETRIC DETERMINATION OF IRON, p. 1
to 5.
Skoog and West, Fundamentals of Analytical Chemistry, 2nd ed., Chapter 29.
Vogel, A Textbook of Quantitative Inorganic Analysis, 3rd Ed., p. 294, 310 and 787.
Related Questions
1. How would you find the solution for this dilution and absorbance problem?
What would the set-up for solving this look like?
(A = 0.0252C(ppm) - 0.0162)
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How do I complete this problem?
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How do I find Concentration?
flask
Calculate solution Concentration (M)
Volume stock of 0.40 M CuSO4 (ml)
Volume of flask (ml)
Absorbance at 635 nm(a.u.)
1
2.0
10
.185
2
4.0
10
.362
3
6.0
10
.510
4
8.0
10
.674
5
10.0
10
.843
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Answer provided: 2.5% Al2(SO4)3
Please show your complete solution and write your answer clearly and readable. Thank you.
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Find #4 and #7
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I need help please!!
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(Solution AII) Prepare 25.00 mL of ~0.05000 M copper (II) acetate solution from your ~ 0.1250 M solution.
Pipet the required amount of solution (AI) into a 25.00 mL volumetric flask.
Fill it to the mark with distilled water, stopper it and invert several times to mix the solution.
Measure the absorbance of this solution at a wavelength of 610 nm, the wavelength where this compound absorbs light most strongly. (e = 5.97 dm3/mol cm)
Calculate molarity of solution AII
Volume of stock solution AI added via pipette
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Suppose that you follow the procedure and find the absorbance of the final solution to be 0.475. What is the concentration of Fe (mg/L) in the final solution?
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calculate the [FESCN2+] using volumes of stock solutions. Presume that all of the
SCN- ions react. Next, record the light absorbance values of each standard
solution.
Volume
Volume
Volume
[FESCN2+]
Absorbance
Standard
Fe(NO3)3
SCN-
H2O
sample
(mL)
(mL)
(mL)
1
2.50
2.00
20.50
0.1811
2
2.50
1.50
21.00
0.3219
2.50
1.00
21.50
0.4981
4
2.50
0.50
22.00
0.6328
Stock [Fe(NO3)3] = 0.200 M, Stock [SCN-] = 0.0020 M.
%3D
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A copy of your chemistry textbook is found to have a mass of 2.52 x 10³ grams. Using unit analysis, show what the
mass of the copy of your chemistry textbook is in milligrams.
Use one of the following to set up the conversion factor.
1 kg 1000 g
1000 mL-1 L
100 cm=1 m
1000 mg=1 g
1 mL=1 cm³
1000 mm=1m
3
2.52 x 10³ g x
80
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1.
Data & Results
4.0 mglmL
Concentration of stock solution (include units):
Table 1-Beer's Law Plot Data
V Volume of standard
solution dispensed (mL)
M, Diluted concentration
(include units)
Sample
Absorbance
A
2.00 mL
0.084
4.00 mL
0.173
l6.00 mL
0.259
8.00 mL
0.340
E
10.00 mL
0.418
Equation of trendline from Beer's Law plot:
whats the diluted concentration and equation of
trendline from the beers law plot once created?
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Part Il: Determination of Standard Solutions
mL of 0.200
mL H20
added
M Cuso,
diluted
Tube #
M Cuso4-5
H20 added
Absorbance
about 3
0.200
1.346
3.
4.00
1.00
0.945
4
3.00
2.00
0.715
2.00
3.00
0.469
6.
1.00
4.00
0.281
show calculation for Tube #3 diluted concentration:
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AP Questions // Questions 10 - 11) A student creates four solutions with varying
concentration of FeSCN2 and gathers the following data at 298 K using a spectrophotometer
calibrated to 460 nm:
[FESCN]
Absorbance
1.1 x 10-4 M
0.076
1.6 x 10-4 M
0.112
2.2 x 10-4 M
0.167
2.5 x 10-4 M
0.199
On the axis below, create a Beer's Law calibration plot for [FESCN2*]. Draw a best-fit line
through your data points.
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Absorbance
Beer-Lambert's Law (Spectrophotometry) #2
To spectrophotometrically determine the mass percent of cobalt in an ore containing cobalt and some inert
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measured at the wavelength of optimum absorbance. The data are used to create a calibration plot, shown
below.
0.80
0.70-
8 0.60-
0.50-
0.40-
0.30
0.20-
0.10-
++-
0.015
Concentration (M)
A 0.6
g sample of the ore is completely dissolved in concentrated HNO3(aq). The mixture is diluted with
2+
water to a final volume of 50.00 mL. Assume that all the cobalt in the ore sample is converted to Co'(aq).
a. What is the (Co] in the solution if the absorbance of a sample of the solution is 0.74?
b. Calculate the number of moles of CoT(ag) in the 50.00 mL solution.
2+
C. Calculate the mass percent of Co in the 0.630 g sample of the ore.
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Sample
Blank
Standard Solution 1
Standard Solution 2
Standard Solution 3
Standard Solution 4
Standard Solution 5
Water Sample 1
Water Sample 2
Phosphate Concentration
(in ppm)
Y17
0 ppm
0.02 ppm
0.04 ppm
0.08 ppm
0.16 ppm
0.32 ppm
Freeman Lake
0.001
0.325
0.292
0.413
0.315
0.039
0.054
0.049
Absorbance at
2= 690 nm
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x-axis and Absorbance (unitless) on your y-axis for your known solutions. Label the axes
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line to your data. Label the graph with the equation and the R" value. Insert your labeled
graph in the space below.
X
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0.875
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