QUESTION 31 Separation of a mixture of sand, NaCl and CaCO3 Part 3 (Values from this part may be used on parts 1&2) Mass of evaporating dish and sand 8.32 g Mass of evaporating dish Mass of sad 714 g Percent of sand a) What is the mass of sand in this sample? b) What is the mass percent sand in this sample? For the toolbar, press ALTF10 (PC) or ALT+FN+F10 (Mac). BIUS Paragraph Arial Ω Click Save and Submit to save and submit. Click Save All Answers to save all ans

Trial 1 Trial 2 Trial 3 Vinegar Volume (mL) 5.00 5.00 5.00 Final buret reading of NaOH(mL) 34.96 32.38 33.12 Initial buret reading of NaOH(mL) 4.85 2.30 2.98 Volume of NaOH dispensed (mL) 30.11 30.08 30.14   Compare the experimental process of your three trials above. Was one trial more accurate than the others? Why? (What are you basing this decision on?) Suppose the concentration of the NaOH solution was 0.5 M instead of 0.1 M. Would this titration have required more, less, or the same amount of NaOH solution for a complete reaction? Suppose you used 0.5 M NaOH to titrate your vinegar sample instead of 0.1 M. What effect does the concentration of base added have on the reliability of the results of your titration?

Consider the following sets of replicate measurements: (1) Calculate the mean and standard deviation of Group A. (2) Determine the confidence interval at 95% confidence level. Assume the data here are the only knowledge you have and no previous measurements are available.

Experiment 3: Determination of the Average Mass of a Penny  Number of pennies: 5 Mass of pennies (weighed together): 13.2 Mass of penny 1: 2.5 Mass of penny 2: 2.5 Mass of penny 3: 2.6 Mass of penny 4: 2.5 Mass of penny 5: 3.1 please help me with this part and show me all step  ??????? ???? ?? ? ?????=??? ?? ?ℎ? ?????????? ?????? ?? ?ℎ? ???? ???????/5  1. Total Mass of five pennies (weighed separately): 2. Average mass of a penny (using mass of five pennies weighed together)

Data Collection Mass of the original sample of mixture (g) 1.547 Mass of recovered naphthalene (g) 0.511 Mass of recovered 3-nitroaniline (g) 0.480 Mass of recovered benzoic acid (g) 0.472 % by mass of naphthalene in original sample % by mass of 3-nitroaniline in original sample % by mass of benzoic acid in original sample Total percent recovered You find a separatory funnel set up in a fume hood. There are clearly two visible layers. Describe a method you could use to determine which layer is the aqueous layer. Normal BIIIU X2| X² | → EE E fx | ® If you had a mixture of butyric acid and hexane, how would you separate the two compounds? Normal BII|U X2 | X² | → fx |

Table 2: Masses of compounds used and observations NaCl CuSO4-5H20 (NH4)2Fe(SO4)2 Appearance of solid Type response here. Type response here. Type response here. Mass of vial and 12.8364 12.7398 12.9445 compound (g) Mass of emptied vial (g) 11.6023 11.4888 11.9221 Mass of compound used (g) Type response here. Type response here. Type response here.

Data Trial 1 Trial 2 Mass of empty crucible with lid 26.698g 26.687g Mass of Mg metal, crucible, and lid 27.060g 27.046g Mass of MgO, crucible, and lid 27.291g 27.273g Subtract the mass of the crucible and lid (row 1 in the chart) from the total mass of MgO, crucible, and lid (row 3 in the chart) to find the mass of magnesium oxide for each trial. This is the actual yieldof magnesium oxide for each trial. Trial 1:593g Trial 2:586g (Just write out how you got the actual yields for both trials)

Trial 1 Trial 2   Initial Buret Reading 0.05 mL 0.02 mL   Final Buret Reading 25.25 mL 23.22 mL   Volume of base used       Molarity of base used 0.1045 M 0.1045 M   Volume of vinegar used 5.00 mL 5.00 mL

ch-Blackboard... on-CLEARED4 cientific Method? 7... 2 QUESTION 8 The mass of one mole of water is 18.02 g. True O False Click Save and Submit to save and submit. Click Save All Answers 90 #5 16 MAR 1 23 5 245 6 tv 100 7

105 g of MgCl2 contains ________ mol MgCl2. Group of answer choices 1.76 1.10 1.06 x 1024 6.62 x 1023 105

Please answer all three questions on the prelab section. Thank you.

sorry about my last response i copied the same question twice. here is the homework i need help withuse both picture do expriement Error

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une Emmanuel Lab Partner(s): Martin k / Martin 0 Data Sheet volume of unknown sample (mL) mass of filter paper (g) mass of filter paper + solid Ba3(PO4)2(g) Calculation: mass of solid Ba3(PO4)2 (g) 1.885 - 0.5-1.315 Calculation: molar mass of Ba3(PO4)2 (g/mol) 737.33 (3)+30.97(2)+8(16) moles of Ba3(PO4)2 Calculation: 1323C Calculation: moles of BaCl2 Stoichiometry Lab 400mL 0.57 g 0.1.885 1.329

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Table 2: Masses of compounds used and observations NaCI CUSO4•5H2O (NH4)2Fe(SO4)2 Appearance of solid Type response here. Type response here. Type response here. Mass of vial and 12.8364 12.7398 12.9445 compound (g) Mass of emptied vial (g) 11.6023 11.4888 11.9221 Mass of compound used (g) Type response here. Type response here. Type response here. Volume of prepared solution = Type response here. Mass of sodium chloride used = Type response here.

What is the average ratio in this chart? Please show me the calculation too!    Sample 1 2 3 Calculations for sample 1 Mass of aluminum dish   1.24g 1.26g 1.24g - Mass of aluminum dish + Epsom salt   1.70g 1.94g 1.80g -   Epsom salt, original (hydrated) mass 0.46g 0.68g 0.56g 1.70g – 1.24g = 0.46g Mass of aluminum dish + Epsom salt after heating 1.42g 1.62g 1.61g   Epsom salt, heated (dehydrated) mass 0.18g 0.36g 0.37g 1.42g- 1.24g = 0.18g Mass of water 0.28g 0.32g 0.19g 0.46g – 0.18g = 0.28g Moles of magnesium sulfate 0.0015mol 0.0030mol 0.0031mol 0.18g x (1mol/120.37g)= 0.0015mol Moles of water 0.016mol 0.018mol 0.011mol 0.28g x (1mol/18.02g) = 0.016mol Ratio of moles water: moles of magnesium sulfate 32:3 18:3 11:3.1 0.016 : 0.0015= 32:3 Average Ratio

The volume amount of vinegar used was

You are working in a hospital and you saw that a patient took 500 mg of ibuprofen but the chart specify 900mg. What is the percent error?a) 55% b) 180% c) 44% d) 60%