une Emmanuel Lab Partner(s): Martin k / Martin 0 Data Sheet volume of unknown sample (mL) mass of filter paper (g) mass of filter paper + solid Ba3(PO4)2(g) Calculation: mass of solid Ba3(PO4)2 (g) 1.885 - 0.5-1.315 Calculation: molar mass of Ba3(PO4)2 (g/mol) 737.33 (3)+30.97(2)+8(16) moles of Ba3(PO4)2 Calculation: 1323C Calculation: moles of BaCl2 Stoichiometry Lab 400mL 0.57 g 0.1.885 1.329 Emmanuel Parmer(s): Martin / Martin O Data Sheet volume of unknown sample (mL) mass of filter paper (g) mass of filter paper + solid Ba3(PO4)2(g) Calculation: mass of solid Ba3(PO4)2 (g) 1.885 - 0.5±1.315 4010AL 0.57 0+.885- 1.320 Calculation: molar mass of Bas(PO4)2 (g/mol) 737.33 (3)+30.97(2)+8(16) 601.93g/m moles of Ba3(PO4)2 Calculation: 131 1329 = 0.002185 moles 601.93 Calculation: moles of BaCl2 3×0002185= 0.00655 Stoichiometry Lab 601099 0.002185moles 0.00065moles
une Emmanuel Lab Partner(s): Martin k / Martin 0 Data Sheet volume of unknown sample (mL) mass of filter paper (g) mass of filter paper + solid Ba3(PO4)2(g) Calculation: mass of solid Ba3(PO4)2 (g) 1.885 - 0.5-1.315 Calculation: molar mass of Ba3(PO4)2 (g/mol) 737.33 (3)+30.97(2)+8(16) moles of Ba3(PO4)2 Calculation: 1323C Calculation: moles of BaCl2 Stoichiometry Lab 400mL 0.57 g 0.1.885 1.329 Emmanuel Parmer(s): Martin / Martin O Data Sheet volume of unknown sample (mL) mass of filter paper (g) mass of filter paper + solid Ba3(PO4)2(g) Calculation: mass of solid Ba3(PO4)2 (g) 1.885 - 0.5±1.315 4010AL 0.57 0+.885- 1.320 Calculation: molar mass of Bas(PO4)2 (g/mol) 737.33 (3)+30.97(2)+8(16) 601.93g/m moles of Ba3(PO4)2 Calculation: 131 1329 = 0.002185 moles 601.93 Calculation: moles of BaCl2 3×0002185= 0.00655 Stoichiometry Lab 601099 0.002185moles 0.00065moles
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question

Transcribed Image Text:une
Emmanuel
Lab Partner(s): Martin k / Martin 0
Data Sheet
volume of unknown sample (mL)
mass of filter paper (g)
mass of filter paper + solid Ba3(PO4)2(g)
Calculation:
mass of solid Ba3(PO4)2 (g)
1.885 - 0.5-1.315
Calculation:
molar mass of Ba3(PO4)2 (g/mol)
737.33 (3)+30.97(2)+8(16)
moles of Ba3(PO4)2
Calculation:
1323C
Calculation:
moles of BaCl2
Stoichiometry Lab
400mL
0.57 g
0.1.885
1.329

Transcribed Image Text:Emmanuel
Parmer(s): Martin / Martin O
Data Sheet
volume of unknown sample (mL)
mass of filter paper (g)
mass of filter paper + solid Ba3(PO4)2(g)
Calculation:
mass of solid Ba3(PO4)2 (g)
1.885 - 0.5±1.315
4010AL
0.57
0+.885-
1.320
Calculation:
molar mass of Bas(PO4)2 (g/mol)
737.33 (3)+30.97(2)+8(16)
601.93g/m
moles of Ba3(PO4)2
Calculation:
131 1329 = 0.002185 moles
601.93
Calculation:
moles of BaCl2
3×0002185= 0.00655
Stoichiometry Lab
601099
0.002185moles
0.00065moles
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