Trial 1Trial 2 Initial Buret Reading0.05 mL0.02 mL Final Buret Reading25.25 mL23.22 mL Volume of base used Molarity of base used0.1045 M0.1045 M Volume of vinegar used5.00 mL5.00 mL The Molarity of Acetic Acid in VinegarEnter the values not given. Use units as appropriate, and enter usingregular notation with the correct sf. Use leading zeroes if a number is lessthan 1.Data used =Trial _1__Trial _2__2.6334 mol2.4244 molMoles of base used in titrationMoles of acetic acid neutralized2.6334 mol2.4244 molin vinegar sampleMolarity of acetic acid in0.5268 M0.4864 Mvinegar0.5066 MAverage Molarity The Mass Percent of Acetic Acid in VinegarUse your two best sets of results along with calculated values in theprevious table to determine the mass percent of acetic acid in vinegar.Use units as appropriate, and enter using regular notation with the correctsf. Use leading zeroes if a number is less than 1.Data used =Trial_1_Trial _2_Mass of in vinegar sampleMass of vinegar sample (assumedensity = 1.00 g/mL)Mass Percent of in vinegarAverage Mass Percent

The molarity of acetic acid in the vinegar can be calculated using the formula: No of moles of acetic acid = No of moles of NaOHMacetic acid × Vacetic acid = MNaOH × VNaOH VNaOH = Final Buret Reading - initial buret readingThe table is completed as follows:Now, molarity = no of moles in 1 L of the solution. Thus, assume volume is 1L or 1000mL, no of moles = Molarity. Also, no of moles = Mass/Molar mass Molar mass of acetic acid = 60.052g/mol Thus, the mass of acetic acid in 1L solution = Molarity×Molar mass ......(used to calculate the mass of acetic acid) Also, density = Mass/Volume So, Mass = Density× Volume ......(used to calculate the mass of the vinegar) Mass% = (Mass of acetic acid/Mass of vinegar) ×100

Answered: The Molarity of Acetic Acid in Vinegar…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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	Trial 1	Trial 2
Initial Buret Reading	0.05 mL	0.02 mL
Final Buret Reading	25.25 mL	23.22 mL
Volume of base used
Molarity of base used	0.1045 M	0.1045 M
Volume of vinegar used	5.00 mL	5.00 mL