Trial 1 Trial 2 Trial 3 Moles HCI (mols) (Use the balanced equation to 7. create a mole ratio to convert moles of NaOH to moles of HCI) 0.00267168 0.00271584 0.00272688 Part 6 of 10 Trial 1 Trial 2 Trial 3 0.02420 0.0284 Volume of HCL (L) 8. |(1L = 1000 mL) 0.02500 * 0.02500 e 0.02500 a 0.02500 Part 7 of 10 Trial 1 Trial 2 Trial 3 Molarity HCl (M) moles solute 9. (molarity liters solution
Trial 1 Trial 2 Trial 3 Moles HCI (mols) (Use the balanced equation to 7. create a mole ratio to convert moles of NaOH to moles of HCI) 0.00267168 0.00271584 0.00272688 Part 6 of 10 Trial 1 Trial 2 Trial 3 0.02420 0.0284 Volume of HCL (L) 8. |(1L = 1000 mL) 0.02500 * 0.02500 e 0.02500 a 0.02500 Part 7 of 10 Trial 1 Trial 2 Trial 3 Molarity HCl (M) moles solute 9. (molarity liters solution
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
Find Molarity for HCl for Trials one through three
![0.02420
0.02460
0.02470
Volume NaOH Used (L)
5.
(1L = 1000 mL)
Part 4 of 1o
Trial 1
Trial 2
Trial 3
Moles NaOH (mols)
2.671
0.00271584
0.00272688
6.
(The concentration of the
NaOH solution is 0.1104 M)
Part 5 of 10
Trial 1
Trial 2
Trial 3
Moles HCI (mols)
(Use the balanced equation to
7. create a mole ratio to convert
moles of NaOH to moles of
HCI)
0.00267168
0.00271584
0.00272688
Part 6 of 10
Trial 1
Trial 2
Trial 3
0.02420
0.0284'
x
0.02500
8.
Volume of HCL (L)
(1L = 1000 mL)
d 0.02500
o 0.02500
O 0.02500
Part 7 of 10
Trial 1
Trial 2
Trial 3
Molarity HCl (M)
moles solute
9.
molarity
liters solution](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9c10e4f5-e278-4bd7-8092-f6a430c865ac%2F93d2f04b-3db8-45aa-b872-f4d65b78fd0e%2Fc895hci_processed.png&w=3840&q=75)
Transcribed Image Text:0.02420
0.02460
0.02470
Volume NaOH Used (L)
5.
(1L = 1000 mL)
Part 4 of 1o
Trial 1
Trial 2
Trial 3
Moles NaOH (mols)
2.671
0.00271584
0.00272688
6.
(The concentration of the
NaOH solution is 0.1104 M)
Part 5 of 10
Trial 1
Trial 2
Trial 3
Moles HCI (mols)
(Use the balanced equation to
7. create a mole ratio to convert
moles of NaOH to moles of
HCI)
0.00267168
0.00271584
0.00272688
Part 6 of 10
Trial 1
Trial 2
Trial 3
0.02420
0.0284'
x
0.02500
8.
Volume of HCL (L)
(1L = 1000 mL)
d 0.02500
o 0.02500
O 0.02500
Part 7 of 10
Trial 1
Trial 2
Trial 3
Molarity HCl (M)
moles solute
9.
molarity
liters solution
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