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If you needed 200 L of 6M HCl for your pool, what volume of your unknown HCl would you need to add instead( if it's not 6M) SHOW WORK!

If you needed 200 L of 6M HCl for your pool, what volume of your unknown HCl would you need to add instead( if it's not 6M) SHOW WORK!

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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If you needed 200 L of 6M HCl for your pool, what volume of your unknown HCl would you need to add instead( if it's not 6M) SHOW WORK!

M= 78 mols Molarity of NaOH calculated from previous section_ D Trial 1 D Unknown number or letter Final ml NaOH Initial mL NaOH Total mL NaOH moles NaOH (calculated) moles HC1 Trial 2 D 13.25mL 25.5mL same as???) mL HCl (measured) M HCI (moles/L!) 0.080m 0.00 mL 13.25 mL 13.25 mL 12.25 mL 0.00106 moles 0009% moles 25 mL 25 mL 0.0424m 0.392 Trial 3 D Trial 4 38.00 m2 11.01 mL oil to noreni 25.00 mL m/ 0.04 1920X1 25.5 mL 12.50mL 11.0.1 m2 0.080 x 0.01225 = 0.00098 0.001 moles 0.000808 moles SELA (calculated, and 0.00 106 mcles 0.0098 moles 0.001 moles 0.000808mues 080 x 0.0125 0.001 moles Average HCI M 0.12668 m (remember, trial one may be omitted from the average if it was sloppy) Standard deviation m 0.032 32 TI 0.080 x 0.1325mL = 0.00 166 moles 0.00 mL Ta best m 25.00 ML 4 3 Average deviation Show HCI molarity calculation for trial 3 (starting with mL NaOH): 0.080 m NaOH x 0.01250L NaOH = 0.001 mois NACH 0.001 mois NaOH 1 mol HCl = 0.001 MOIS HCl I mol NaOH 0.080 x 6.0llol = 0.000808 Question: 0.001 mois HCl 0.0264 = 0.04 m HC1 If you needed 200 L of 6M HCl for your pool, what volume of your unknown HCl would you need to add instead (if it is NOT 6 M)? SHOW WORK! You may dispose of your NaOH solution down the drain (since NaOH is the major component of Drano®), and a stronger concentration will be required for next week. Also, turn in discussion- see end of lab. TA Initials
Transcribed Image Text:M= 78 mols Molarity of NaOH calculated from previous section_ D Trial 1 D Unknown number or letter Final ml NaOH Initial mL NaOH Total mL NaOH moles NaOH (calculated) moles HC1 Trial 2 D 13.25mL 25.5mL same as???) mL HCl (measured) M HCI (moles/L!) 0.080m 0.00 mL 13.25 mL 13.25 mL 12.25 mL 0.00106 moles 0009% moles 25 mL 25 mL 0.0424m 0.392 Trial 3 D Trial 4 38.00 m2 11.01 mL oil to noreni 25.00 mL m/ 0.04 1920X1 25.5 mL 12.50mL 11.0.1 m2 0.080 x 0.01225 = 0.00098 0.001 moles 0.000808 moles SELA (calculated, and 0.00 106 mcles 0.0098 moles 0.001 moles 0.000808mues 080 x 0.0125 0.001 moles Average HCI M 0.12668 m (remember, trial one may be omitted from the average if it was sloppy) Standard deviation m 0.032 32 TI 0.080 x 0.1325mL = 0.00 166 moles 0.00 mL Ta best m 25.00 ML 4 3 Average deviation Show HCI molarity calculation for trial 3 (starting with mL NaOH): 0.080 m NaOH x 0.01250L NaOH = 0.001 mois NACH 0.001 mois NaOH 1 mol HCl = 0.001 MOIS HCl I mol NaOH 0.080 x 6.0llol = 0.000808 Question: 0.001 mois HCl 0.0264 = 0.04 m HC1 If you needed 200 L of 6M HCl for your pool, what volume of your unknown HCl would you need to add instead (if it is NOT 6 M)? SHOW WORK! You may dispose of your NaOH solution down the drain (since NaOH is the major component of Drano®), and a stronger concentration will be required for next week. Also, turn in discussion- see end of lab. TA Initials
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