PHYS 1302 Exam 2 REVIEW Sample Spring2024

docx

School

Texas A&M International University *

*We aren’t endorsed by this school

Course

1302

Subject

Chemistry

Date

Feb 20, 2024

Type

docx

Pages

Uploaded by BrigadierElementSeal88

PHYS 1302 – Exam 2 REVIEW SAMPLE Test Coverage: Chapters 18, 19 & partly 20 Test Instructions Exam 2 Schedule: OPENS at 12 am on Thursday, February 15 th and CLOSES at 11:59 pm on Friday, February 16 th (Time to test: 75 minutes maximum) Exam 2 Additional Instructions: >Use Lockdown Browser and Monitor (with microphone). >Take Exam 2 on Canvas under Modules Tab or Quizzes Tab or Assignments Tab. >Use dark lead pencil/pen and 1- 2 pcs white scratch paper for scribbling/showing work. NOTE: This REVIEW Material is NOT allowed while testing. >Use your own 1-2 pcs 4”x6” index cards as formula sheet. Both sides allowed. Prepare your formula sheet at least a day prior to the exam. > TI graphing calculator is allowed. Scientific calculator is also activated in Lockdown Browser usually located at the top left corner or top right corner in the test area. > No water or restroom breaks. No other electronic devices allowed while taking the test. This REVIEW MATERIAL is NOT allowed while testing. >Strong Suggestion -- Read the entire exam. Do the problems you know you can do first. Next do the problems you think you can do. Anything else is last. > Show complete work for the problems (FRQs) and then apply the rules of sig. fig. in your final answers. Submit your Exam 2 SHOW WORK at the designated drop box IMMEDIATELY after taking the test, for possible extra credits. I. Multiple Choice. Bubble in the letter of the best answer on your scantron. ( 2 pts @ ) ___1. Two resistors with values of 6.0  and 12.0  are connected in parallel. This combination is connected in series with 4.0  resistor. What is the equivalent resistance of this combination? a. 0.50  b. 2.0  c. 8.0  d. 22  ___2. Increasing the separation of the two charged parallel plates of a capacitor when they are disconnected from a battery will produce what effect on the capacitor? a. It will increase the charge. c. It will increase the capacitance. b. It will decrease the charge. d. It will decrease the capacitance. ___3. Changing the dielectric of two charged parallel plates of a capacitor from vacuum to mica will produce what effect on the capacitor? a. It will increase the charge. c. It will increase the capacitance. b. It will decrease the charge. d. It will decrease the capacitance.

___4. When electrons move through a metal conductor a. they move in straight line through the conductor. b. they move in zigzag patterns because of repeated collisions with the vibrating metal atoms. c. the temperature of the conductor decreases. d. they move at the speed of light in a vacuum. ___5. How does the potential difference across the bulb in a flashlight compare with the terminal voltage of the batteries used to power the flashlight? a. The potential difference is greater than the terminal voltage. b. The potential difference is less than the terminal voltage. c. The potential difference is (approx.) equal to the terminal voltage. d. It cannot be determined unless the internal resistance of the batteries is known. ___6. Which sentence best characterizes electric conductors? a. Charges on their surface do not move. b. They have high tensile strength. c. Electric charges move freely in them. d. They are not good heat conductors. II. Short answer. Use Kirchhoff’s rules (KR) to find the equations. 1. Using KR 1, what is the equation at the lower junction? 2. Using KR 2, what is the equation at the left loop?

III. Problem. Answer the following problems. Show COMPLETE and NEAT WORK ! No work, no credit. Write the equation(s)/solution/work, and answer(s) on the space provided for. Be sure to apply the rules of significant figures in your final answers. 1. (3 pts) Resistances in Series-Parallel : What is the equivalent resistance for the resistors in the following circuit? The left and right network of resistors are connected in the middle. Round final answer to 2 sig. fig. Equation(s)/Solution/Work: Answer:

Your preview ends here

Eager to read complete document? Join bartleby learn and gain access to the full version

Access to all documents
Unlimited textbook solutions
24/7 expert homework help

2. (3 pts) Capacitances in Series-Parallel : The figure below shows 3 capacitors, of equal capacitance C = 8.2 microfarads = 8.2 x 10 -6 F, connected to a battery of voltage V. What is the equivalent capacitance of this combination? Round final answer to 2 sig. fig. Equation(s)/Solution/Work: Answer:

1. (6 pts) Resistors in Parallel: Three (3) resistors (R 1 = 2.50  , R 2 = 4.50  , and R 3 = 8.97  ) are connected in parallel to an operating or terminal voltage of 12.0 V. Determine the following: (a) R eq . (b) V 1 . (c) I 1 . V 2 . I 2 . V 3 . I 3 . I T . Round final answers to 3 sig. fig. Equation(s)/Solution/Work: Answer(s):

Kirchhoff’s Rules and Example: Current in a junction = Current out from the same junction or node I in = I out or ΣI junction = 0

Your preview ends here

Eager to read complete document? Join bartleby learn and gain access to the full version

Access to all documents
Unlimited textbook solutions
24/7 expert homework help

Figure 3. Sign conventions for Kirchhoff’s rules: Traversing a battery or voltage source (or emfs, ԑ ). Figure 4. Sign convention for Kirchhoff’s rules: Traversing a resistor. The algebraic sum of the voltages around a loop is zero.

Tips for solving using matrices on TI Graphing Calculator: 1) Arrange the generated equations from the multiloop circuit like this. I 1 – I 2 – I 3 = 0 I 1 + 2 I 2 + 0 I 3 = – 3 0 I 1 + 2 I 2 – 3 I 3 = – 6 2) Convert the above equations into augmented matrix. [ 1 − 1 − 1 − 0 1 20 − 3 0 2 − 3 − 6 ] 3) Turn-on calculator (these steps are intended for TI-83, TI-84, TI-84 Plus calculator. For TI Inspire, refer to your calculator manual or goggle the procedure). Press 2 nd then matrix . Move cursor to EDIT . Press EDIT or enter (where cursor highlights 1: [A]). 4) Edit the dimension of MATRIX A to 3 x 4 . Enter all values from #2 into MATRIX A. Every number your entered, press enter after. Enter negative values using the appropriate sign (-), not the minus – sign. 5) Once all values are entered in the matrix of the calculator, click 2 nd then quit . Don’t

Your preview ends here

Eager to read complete document? Join bartleby learn and gain access to the full version

Access to all documents
Unlimited textbook solutions
24/7 expert homework help

worry the values you entered are saved in MATRIX A. 6) Click again 2 nd then matrix . Move cursor to MATH . Inside MATH , move cursor down up to B: rref( . Select that command. 7) rref( will be on your calculator screen. Now press again 2 nd then matrix . Select or press 1: [A] 3 x 4 (where the matrix values were entered). 8) Rref([A] will appear on your calculator screen. Press ) to close the command. After that, press enter . 9) Your screen displays the answers like this. The last column is rounded to 3 decimal places. [ 1 00 − 0.273 0 10 − 1.364 0 01 1.091 ] 10) The first 1 in the first column corresponds to the value of current 1, I 1 = − ¿ 0.273. The second 1 in the second column corresponds to the value of current 2, I 2 = − ¿ 1.364. The third 1 in the third column corresponds to the value of current 3, I 3 = 1.091. 11) You can also convert the decimal values of the current to fraction values. Press math on your calculator then select 1: Frac . Press enter . Then press enter again. Your answer should look like the one below. [ 1 00 − 3 / 11 0 10 − 15 / 11 0 01 12 / 11 ] 12) Again, the first 1 in the first column corresponds to the value of current 1, I 1 = − ¿ 3/11. The second 1 in the second column corresponds to the value of current 2, I 2 = − ¿ 15/11. The third 1 in the third column corresponds to the value of current 3, I 3 = 12/11.

4. (6 pts) Kirchhoff’s Rules : For the circuit shown below, find the I 1 , I 2 and I 3 . Round final answers to 3 sig. fig. Use the values provided below for resistances and emfs. R 1 = 12.0   1 = 9.00 V R 2 = 15.0   2 = 12.0 V R 3 = 19.0   3 = 6.00 V Equation(s)/Solution/Work: Answer: X Y

KEY – PHYS 1302 – Exam 2 REVIEW SAMPLE I. Multiple Choice 1. C 2. D 3. C 4. B 5. C 6. C II. Short answer 1. I 1 – I 2 + I 3 = 0 or – I 1 + I 2 – I 3 = 0 2. – E 2 – I 2 R 2 + E 1 – I 1 R 1 = 0 III. Problem 1. R eqv = 2.3  2. C eqv = 5.5 microfarads = 5.5 x 10 -6 F 3. (a) R eqv = 1.36  (b) V 1 = V 2 = V 3 = V T = V = 12.0 V (c) I 1 = 4.80 A I 2 = 2.67 A I 3 = 1.34 A I T = 8.82 A 4. I 1 = | - 0.0173 A | = 0.0173 A I 2 = | - 0.186 A | = 0.186 A

Your preview ends here

Eager to read complete document? Join bartleby learn and gain access to the full version

Access to all documents
Unlimited textbook solutions
24/7 expert homework help

I 3 = | - 0.169 A | = 0.169 A The chosen original current directions need to be reversed (if negative) to have correct current flow (directions). Hence, write currents with positive values or NO + sign, just the numbers. This is the reason why the absolute value sign was used for the electric current values.