CHM1045L_Exp_4_DATA_SHEET
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DATA SHEET
Name Janae Seays_____ Date 02/12/24___________
Lab Partner_____________ Instructor________________
E X P E R I M E N T 4 : Exploring the Mole
Show calculations for station 1 to 14:
Station 1
Number of moles of SiO2 = 9.106g/ 60.08 g. mol^-1 = 0.15
Number of atoms of Si = mol x 6.0 = 9.03 9.03 x 10^22
Station 2
No of molecules = 1.25 x 10^22 molecules Mols of theobromine = 1.25 x 10^22/ 6.022 x 10^23 = 0.0208 mols Molar mass = 180.164 g/ mol
Mass = mols x Molar Mass
0.0208 x 180.164
= 3.74 g
Station 3
Station 4
5.749/100.0869 mol = 0.0574 mol CaCO3
Station 5
Molar Mass of Cu = 63.55 g/mol
Mass (Cu)= 1.106
= 1.106 g/ 63.55 g/mol = 1.74 x 10^-2 mol Station 6
8.358 g / 58.44 g/mol = 0.143 mol
Station 7
Station 8
Station 9
=1.19g g
L
x 2,740.5 x 10^-3 L =3.2612g = 6.22 x 10^23 x 0.0909mol = 5.4739 x 10^ 22
Station 10
Station 11
111.70 g/ mol + 48.00 g/mol = 159.70 g/mol 4.35 x 10^22 atoms / 6.022 x 10^23 atoms/mol 0.072 moles
0.072 x 159.70 g/mol - 11.54 grams 3* 12.01 g/mol + 7* 1.01 g/mol + 1 * 16.00 g/mol = 60.08 g/mol
18.078 g/ 60.08 g/mol = 0.3002 moles
5.42 x 10^23
Station 12
22.99 + 1.01 + 12.01 + (3 x 16.00) = 84.01g/mol
2.297 g / 84.01 g/ mol = 0.027342 mol
6.00 g/ 102.711 g x 100 % = 5.842%
22.99 g/mol + 35.45 g/mol = 58.44 g/ mol 6.00g/ 58.44 g/mol = 0.1027 mol Station 13
22.99 + 1.01 +12.01 + (3 x 16.00) = 84.01 g/ mol
2.297 g / 84.01 g/ mol = 0.027342 mol
Station 14
0.500 * (400/1000) = 0.200
0.200 x 110.98 = 22.196 22.2 g Show calculation for these Additional Questions:
1.
How many moles of Pb is 9.34 ×
10
15
atoms of Pb?
1 mol = 6.022 x 10^23
9.34 x 10^15 atoms of Pb = 1mol/ 6.022 x
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10^23 atoms x 9.34 x 10^ 15 atoms of Pb = 1.55 x 10^-8 mol
2.
How many grams are in 4.35 moles of Ar?
39.95 g/mol
39.95 g/mol x 4.35 mo; = 174g
3.
How many atoms are in 1.45 g of Ag?
107.87 g/mol 1.45g / 107.87 g/mol 1.45g / 107.87 g/mol x 6.022 x 10^23 atoms/mol
= 8.09 x 10^21 atoms 4.
How many grams are in 1.98 × 10
21
atoms of Fe?
1mol/ 6.022 x 10^23 x 1.98 x 10^ 21
= 0.32879 x 10^-2 mol = 0.32879 x 10^ -2 mol x 55.85 g/mol = 0.184 g
5.
How many moles are in 6.24 × 10
21
molecules of CaSO
4
?
1 mol / 6.022 x 10^23 x 6.24 x 10^ 21 = 1.04 x 10^-2 mol
6.
How many grams are in 17.83 moles of carbon dioxide?
= 12.01g/ mol + 2 x 16.00g mol = 44.01 g/ mol = 17.83 moles x 44.01 g/mol = 784.5 g
7.
How many grams are in 2.38 × 1 mole – 6.022 x 10^23 molecules
10
22
molecules of ammonia (NH
3
)?
1 molecule = 2/ 6.022 x 10^23
= 2.38 x 10^22 / 6.022 x 10^ 23 = 0.395 x 10^-1 moles =3.95 x 10^-2 moles
Moles mass of NH3 = 17.031 g
= 3.95 x 10^-2 mol4w x 17.03 g/mol
= 67.27 x 10 ^-2 g 8.
How many carbon atoms are in 2.65 × 10
23
molecules of C
2
H
6
?
2.65 x 10^23 molecules / 6.023 x 10^23 molecules/ moles
= 0.439980076 mol
(2) (0.439980076 mol) (6.023 x 10^23 atoms/mol)
= 5.3 x 10^23 atoms
9.
How many moles of phosphorus are in 16.2 moles of aluminum phosphate?
16.2 moles
10. How many grams of iron are in 21.6 grams of iron(III) oxide?
15.1 grams iron present 11. How many hydrogen atoms are
in 65.2 grams of Ca(C
2
H
3
O
2
)
2
?
1.5 x 10^24 atoms hydrogen present
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