Chapter SH, Problem 8.36EP

a.

To determine

To write the factor form of expression.

  

Answer to Problem 8.36EP

The height after 0.5 seconds is 21.

Explanation of Solution

Given information:

Height of the apple after t seconds

  

Formula used:

  $\left(a^2-b^2\right)=\left(a-b\right)\left(a+b\right)$

Calculation:

Let H(t) be the height of apple after t seconds

  

So,

= $5^2-{\left(4t\right)}^2$

Comparing above expression with formula

  $=\left(5-4t\right))\left(5-4t\right)$

Hence, factor form is $=\left(5-4t\right))\left(5-4t\right)$ .

b.

To determine

To calculate height after 0.5 seconds.

Answer to Problem 8.36EP

Factor form is $=\left(5-4t\right))\left(5-4t\right)$ .

Explanation of Solution

Given information:

Height of the apple after t seconds

  

Calculation:

Let H(t)be the height of apple after t seconds

  

So, height at 0.5 seconds

  $H\left(0.5\right)=25-16{(0.5)}^2$

On solving,

= $25-16\left(0.25\right)$

On solving,

  $=25-4=21$

Hence, the height after 0.5 seconds is 21.