Chapter SH, Problem 6.8EP

To determine

To calculate each type of fruit cost.

Answer to Problem 6.8EP

Cost of apples are $3.6 and cost of Oranges are $3.5 .

Explanation of Solution

Given information:

  

Calculation:

Let cost of one apple is $ x

Let cost of one Orange is $ y

T having 6 apples and 5 oranges and spent $4.30

Then,

  $6x+5y=4.30\mathrm{.........}(1)$

S having 6 apples and 2 oranges and spent $2.80

Then,

  $6x+2y=2.80\mathrm{............}(2)$

From equation (1) substituting $6x=4.30-5y$in equation (2)

  $4.30-5y+2y=2.80$

On solving,

  $4.30-2.80=3y$

On solving,

  $1.50=3y$

Then,

  $y=0.5$

Substituting $y=0.5$in the equation (1)

  $6x+5(0.5)=4.30$

On solving,

  $6x+2.5=4.30$

On solving,

  $6x=1.80$

On solving,

  $x=0.3$

Cost of apples $=12x$

  $=12(0.3)$

  $=3.6$

Cost of Oranges $=7y$

  $=7(0.5)$

  $=3.5$

Hence, cost of apples are $3.6 and cost of Oranges are $3.5