Chapter SH, Problem 10.6EP

To determine

To find minimum, lower quartile, upper quartile, median and maximum.

Answer to Problem 10.6EP

Minimum=2.58

Lower quartile, m₁₌2.59

Upper quartile, m₂=2.71

Median, m=2.65

Maximum=2.83

Explanation of Solution

Given information:

The price of gases at seven stations

$2.63, $2.59, $2.70, $2.58, $2.83, $2.65, $2.71.

Calculation:

Ordered data set

2.58, 2.59, 2.63, 2.65, 2.70, 2.71, 2.83

Using box-and-whisker plot compare above set of data

Minimum=2.58

Lower quartile

2.58, 2.59, 2.63

Median for lower quartile

m₁=2.59

Upper quartile

2.70, 2.71, 2.83

Median for upper quartile

m₂=2.71

Median

n number of frequencies

n=7

n is odd

Then middle term is median

Median=2.65

Maximum=2.83