Chapter SH, Problem 6.10EP

To determine

To solve system of equation using elimination

  $-5k+4j=8$

  $-5k-6j=-12$

Answer to Problem 6.10EP

  $j=2$

  $k=0$

Explanation of Solution

Given information:

  $-5k+4j=8$

  $-5k-6j=-12$

Calculation:

  $-5k+4j=8\mathrm{.........}(1)$

  $-5k-6j=-12\mathrm{..........}(2)$

In equation (1) and (2), term - 5k is present

Then, substract equation (1) from (2) to eliminate term - 5k

  $\begin{array}{l}-5k+4j=8\\ -(-5k-6j=-12)\\ \overline{0+10j=20}\end{array}$

Then,

  $10j=20$

So,

  $j=2$

Substituting value of j in equation (1)

  $-5k+4(2)=8$

On solving,

  $-5k=0$

On soiving,

  $k=0$