Chapter SH, Problem 14.5.5EP

To determine

To find: The Product of the given numbers

Answer to Problem 14.5.5EP

The Product of $(2m-3)(3m+5)$ is $6m^2+m-15$

Explanation of Solution

Given:

  $(2m-3)(3m+5)$

Calculation:

By using the FOIL method

The first terms are $2m,3m$

Product of first two terms is $2m\times 3m=6m^2$

The outer terms are $2m,5$

Product of outer terms is $2m\times 5=10m$

The inner terms are $-3,3m$

Product of inner terms is $-3\times 3m=-9m$

The last terms are $-3,5$

Product of last terms is $-3\times 5=-15$

By adding all the products

  $(2m-3)(3m+5)=6m^2+10m-9m-15$

  = $6m^2+m-15$ (simplify)

Conclusion:

The Product of $(2m-3)(3m+5)$ is $6m^2+m-15$