Chapter SH, Problem 13.1.2EP

To determine

To find: the mean, median, and mode for the given data

Answer to Problem 13.1.2EP

The mean is $27.1$ .

The median is $26$ .

The modes are $23,32$ .

Explanation of Solution

Given:

Ages of people in an aerobic class $:23,32,19,27,41,21,26,32,23$

Measure of central tendency:

Consider the below data,

  $23,32,19,27,41,21,26,32,23$

Find the mean, median, mode.

Mean:

Mean is sum of data points divided by the number of data points.

Here number of data points is $9$ .

  $\begin{array}{l}Mean=\frac{23+32+19+27+41+21+26+32+23}{5}\\ =\frac{244}{9}\\ \approx 27.1\end{array}$

Hence, the mean is $27.1$ .

Median:

Median is the middle number of the data ordered from lowest to greatest.

Data in increasing order is

  $19,21,23,23,26,27,32,32,41$

Here middle number is $26$ .

Hence, the median is $26$ .

Mode:

Mode is the number or numbers that occur more often.

Data points that occur more often are $23,32$ .

Hence, the modes are $23,32$ .

Conclusion:

Hence, the mean is $27.1$ .

Hence, the median is $26$ .

Hence, the modes are $23,32$ .