Chapter SH, Problem 14.5.4EP

To determine

To find: The Product of the given numbers

Answer to Problem 14.5.4EP

The Product of $(p+6)(p-2)$ is $p^2+4p-12$

Explanation of Solution

Given:

  $(p+6)(p-2)$

Calculation:

By using the FOIL method

The first terms are $p,p$

Product of first two terms is $p\times p=p^2$

The outer terms are $p,-2$

Product of outer terms is $p(-2)=-2p$

The inner terms are $6,p$

Product of inner terms is $6\times p=6p$

The last terms are $6,-2$

Product of last terms is $6(-2)=-12$

By adding all the products

  $(p+6)(p-2)=p^2-2p+6p-12$

  $=p^2+4p-12$ (Simplify)

Conclusion:

Hence, the Product of $(p+6)(p-2)$ is $p^2+4p-12$