Chapter SH, Problem 14.5.2EP

To determine

To find: The Product of the given numbers

Answer to Problem 14.5.2EP

The Product of $(y+5)(y+8)$ is $y^2+13y+40$

Explanation of Solution

Given:

  $(y+5)(y+8)$

Calculation:

By using the FOIL method

The first terms are $y,y$

Product of first two terms is $y\times y=y^2$

The outer terms are $y,8$

Product of outer terms is $y\times 8=8y$

The inner terms are $5,y$

Product of inner terms is $5\times y=5y$

The last terms are $5,8$

Product of last terms is $5\times 8=40$

By adding all the products

  $(y+5)(y+8)=y^2+8y+5y+40$

  = $y^2+13y+40$ (simplify)

Conclusion:

Hence, The Product of $(y+5)(y+8)$ is $y^2+13y+40$