Precalculus: Graphical, Numerical, Algebraic Common Core 10th Edition
Precalculus: Graphical, Numerical, Algebraic Common Core 10th Edition
10th Edition
ISBN: 9780134673301
Author: Waits, Foley, Kennedy, Bock Demana
Publisher: PEARSON
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Chapter P.2, Problem 20E
Solution

Find the perimeter and area of the figure determined by the points.

Perimeter = 16

Area = 16

Given information:

The given points are (-2,-2), (-2, 2) (2, 2) (2,-2)

Concept used:

  • First, find the value for x on the x-axis.
  • Next, find the y-value on the y-axis.
  • The point should be plotted at the intersection of x and y.
  • Finally, plot the point on your graph at the appropriate spot.
  • Then join all the points to make a closed figure for calculating perimeter and area.

Calculation:

The given points are A(-2,-2), B(-2, 2) C(2,2) D(2,-2).

Plotting the points in the graph -

  Precalculus: Graphical, Numerical, Algebraic Common Core 10th Edition, Chapter P.2, Problem 20E

Perimeter of enclosed figure ABCD is = AB+BC+CD+DA

Using distance formula −

A(-2,-2), B(-2, 2)

  AB=(x1−x2)+(y1−y2)=(−2−(−2))2+(−2−2)2=(−2+2)2+(−4)2=(0)2+16=4

AB = CD

So CD =4

B(-2, 2) C(2,2)

  BC=(x1−x2)+(y1−y2)=(−2−2)2+(2−2)2=(−4)2+(0)2=16=4

BC=DA

So DA=4

Perimeter of enclosed figure ABCD-

   AB+BC+CD+DA=4+4+4+4=16

Area of enclosed figure ABCD is −

As AB=BC=CD=DA

So ABCD is a square

Area of square ABCD = side2

   Area= (4) 2 =16

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Chapter P.2, Problem 19E
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Chapter P.2, Problem 21E

Chapter P Solutions

Precalculus: Graphical, Numerical, Algebraic Common Core 10th Edition

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