Precalculus: Graphical, Numerical, Algebraic Common Core 10th Edition
Precalculus: Graphical, Numerical, Algebraic Common Core 10th Edition
10th Edition
ISBN: 9780134673301
Author: Waits, Foley, Kennedy, Bock Demana
Publisher: PEARSON
Expert Solution & Answer
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Chapter P.7, Problem 22E
Solution

Solve the inequality graphically.

  x>0⋅793 or x<2⋅207

Given:

The inequality is, 4x2−12x+7<0

Concept Used:

  • The relationship between two values that are not equal is defined by inequalities.
  • Inequality means not equal.
  • Generally, if two values are not equal, we use “not equal symbol (?)”. But to compare the values, whether it is less than or greater than, different inequalities are used.
  • Factorization is the process of reducing the bracket of a quadratic equation, instead of expanding the bracket and converting the equation to a product of factors which cannot be reduced further. 

Calculation:

  4x2−12x+7<0

The graph of 4x2−12x+7<0 is −

  Precalculus: Graphical, Numerical, Algebraic Common Core 10th Edition, Chapter P.7, Problem 22E

  0⋅793<x<2⋅207

Note that the given inequality is true for the values of x>0⋅793 and for the values of x<2⋅207

Thus, the solution of the given inequality is x>0⋅793 or x<2⋅207

Interval notation (0⋅793,2⋅207)

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Chapter P.7, Problem 21E
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Chapter P.7, Problem 23E

Chapter P Solutions

Precalculus: Graphical, Numerical, Algebraic Common Core 10th Edition

Ch. P.1 - Prob. 1QRCh. P.1 - Prob. 2QRCh. P.1 - Prob. 3QRCh. P.1 - Prob. 4QRCh. P.1 - Prob. 5QRCh. P.1 - Prob. 6QRCh. P.1 - Prob. 7QRCh. P.1 - Prob. 8QRCh. P.1 - Prob. 9QRCh. P.1 - Prob. 10QR
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