Precalculus: Graphical, Numerical, Algebraic Common Core 10th Edition
Precalculus: Graphical, Numerical, Algebraic Common Core 10th Edition
10th Edition
ISBN: 9780134673301
Author: Waits, Foley, Kennedy, Bock Demana
Publisher: PEARSON
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Chapter P.4, Problem 57E
Solution

Determine a and b so that figure ABCD is a parallelogram.

  Precalculus: Graphical, Numerical, Algebraic Common Core 10th Edition, Chapter P.4, Problem 57E , additional homework tip  1

  a=6

  b=5

Given information:

ABCD is a parallelogram.

Concept used:

  • First, find the value for x on the x-axis.
  • Next, find the y-value on the y-axis.
  • The point should be plotted at the intersection of x and y.
  • Finally, plot the point on your graph at the appropriate spot.
  • Then join all the points to make a closed figure for calculating perimeter and area.

Calculation:

ABCD is a parallelogram.

  Precalculus: Graphical, Numerical, Algebraic Common Core 10th Edition, Chapter P.4, Problem 57E , additional homework tip  2

The opposite side of parallelogram are equal.

From figure b is equal to 5

  b=5

AB=CD and BC=AD

Using distance formula −

  AB=(x1x2)+(y1y2)=(02)2+(05)2=(2)2+(5)2=4+25=29

  CD=(x1x2)+(y1y2)=(4a)2+(05)2=16+a28a+(5)2=16+a28a+25=a28a+25+16=a28a+41

As AB=CD

  29=a28a+41onsquaringbothside29=a28a+41a28a+4129=0a28a+12=0equation1

  AD=(x1x2)+(y1y2)=(04)2+(00)2=(4)2+(0)2=16=4

  BC=(x1x2)+(y1y2)=(2a)2+(55)2=4+a24a=a24a+4=a24a+4

BC=AD

  a24a+4=4onsquaringbothsidea24a+4=16a24a+416=0a24a12=0equation2

On comparing equation1 and equation2

  a28a+12=a24a128a4a=12+124a=24a=244a=6

Chapter P Solutions

Precalculus: Graphical, Numerical, Algebraic Common Core 10th Edition

Ch. P.1 - Prob. 1ECh. P.1 - Prob. 2ECh. P.1 - Prob. 3ECh. P.1 - Prob. 4ECh. P.1 - Prob. 5ECh. P.1 - Prob. 6ECh. P.1 - Prob. 7ECh. P.1 - Prob. 8ECh. P.1 - Prob. 9ECh. P.1 - Prob. 10ECh. P.1 - Prob. 11ECh. P.1 - Prob. 12ECh. P.1 - Prob. 13ECh. P.1 - Prob. 14ECh. P.1 - Prob. 15ECh. P.1 - Prob. 16ECh. P.1 - Prob. 17ECh. P.1 - Prob. 18ECh. P.1 - Prob. 19ECh. P.1 - Prob. 20ECh. P.1 - Prob. 21ECh. P.1 - Prob. 22ECh. P.1 - Prob. 23ECh. P.1 - Prob. 24ECh. P.1 - Prob. 25ECh. P.1 - Prob. 26ECh. P.1 - Prob. 27ECh. P.1 - Prob. 28ECh. P.1 - Prob. 29ECh. P.1 - Prob. 30ECh. P.1 - Prob. 31ECh. P.1 - Prob. 32ECh. P.1 - Prob. 33ECh. P.1 - Prob. 34ECh. P.1 - Prob. 35ECh. P.1 - Prob. 36ECh. P.1 - Prob. 37ECh. P.1 - Prob. 38ECh. P.1 - Prob. 39ECh. P.1 - Prob. 40ECh. P.1 - Prob. 41ECh. P.1 - Prob. 42ECh. P.1 - Prob. 43ECh. P.1 - Prob. 44ECh. P.1 - Prob. 45ECh. P.1 - Prob. 46ECh. P.1 - Prob. 47ECh. P.1 - In Exercises 4752, simplify the expression. Assume...Ch. 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