Precalculus: Graphical, Numerical, Algebraic Common Core 10th Edition

10th Edition

ISBN: 9780134673301

Author: Waits, Foley, Kennedy, Bock Demana

Publisher: PEARSON

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Concept explainers

Unitary Method

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Expert Solution & Answer

Chapter P.3, Problem 69E

Solution

(a)

To calculate the statement 2<3 is true by returning the value 1 when 2<3 is entered

Given:

True or false 2<3

Calculation:

In order to calculate the statement 2<3 is true by returning the value 1 when 2<3 is entered , since 3 is greater than 2, on entering 2 less than 3 on calculator, it shows a true statement.

(b)

To calculate the statement 2<1 is false by returning the value 0 when 2<1 is entered.

Given:

True or false 2<1 .

Calculation:

In order to calculate the statement 2<1 is false by returning the value 0 when 2<1 is entered , since 1 is less than 2, on entering 2 greater than 1 on calculator, it shows a false statement.

(c)

To determine which number is larger 799800, 800801 .

800801

Given:

The numbers, 799800, 800801 .

Calculation:

In order to find the larger number , first taking 799800 this number can be written as

799800=1−1800=800−1800

then the other number

800801=1−1801=801−1801

so, 800801 is larger number because in this number subtracting less than 1.

(d)

To determine which number is larger −102101, −103102 .

−102101

Given:

The numbers, −102101, −103102 .

Calculation:

In order to find the larger number , first taking −102101 this number can be written as

−102101=−1−1101=−101−1101

then the other number can be written as

−103102=−1−2102=−102−2102

so, −102101 is larger number.

(e)

To find the value stored in x , it returns 0 when enter 2x+1<4

Given:

2x+1<4

Calculation:

In order to calculate the value of x when it returns o when enter 2x+1<4 , 4 is greater than 2x+1<4 putting x=0 as shown below:

2x+1<4x=020+1<41<4

Chapter P.3, Problem 68E

Chapter P.3, Problem 70E

Chapter P Solutions

Precalculus: Graphical, Numerical, Algebraic Common Core 10th Edition

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Solution Summary: The author explains how to calculate the statement 23 by returning the value 1 and the other number l800801

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Chapter P Solutions