Precalculus: Graphical, Numerical, Algebraic Common Core 10th Edition
Precalculus: Graphical, Numerical, Algebraic Common Core 10th Edition
10th Edition
ISBN: 9780134673301
Author: Waits, Foley, Kennedy, Bock Demana
Publisher: PEARSON
Expert Solution & Answer
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Chapter P.3, Problem 27E
Solution

The solution of the equation t+58−t−22=13 .

  t=319

Given:

The equation, t+58−t−22=13 .

Concept Used:

  • The opposite operation of additions is subtraction and vice-versa.
  • The opposite operation of Multiplication is division and vice-versa.
  • Distributive property: ab+c=a⋅b+a⋅c
  • The least common denominator (LCD) is the smallest number divisible by all the denominators.

Calculation:

In order to solve the given equation, multiply both sides by the LCD of 8, 2, and 3, that is, multiply both sides by 24 to get rid of the denominators and then simplify further using the basic algebraic operations as shown below

  t+58−t−22=13t+58−t−22⋅24=13⋅243t+5−12t−2=83t+15−12t+24=8−9t+39=8−9t+39−39=8−39−9t=−31−9t−9=−31−9t=319

Thus, the solution of the given equation is t=319 .

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Chapter P.3, Problem 26E
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Chapter P.3, Problem 28E

Chapter P Solutions

Precalculus: Graphical, Numerical, Algebraic Common Core 10th Edition

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