Calculus IIIMay I have an expert explained how the terms were simplified into 6(3-x)^2?Thank you, Groupand Simplify Like terms12 (3-x) + (-4x) (3-2) + [4 (3-x)² - 2x (3-2)² ] - 4 (3-x)²Constant termlinear inxQuadratic4(3-2)² - 2x (3-x) = (3-2) (4-22)212 (3-x) + 6 (3-x)² - 4 (3-20)³3

Correct Factored Form:If We Want to Expand: However, if we want Step-by-Step Simplification of the…

Group and Simplify Like terms 12 (3-x) + (-4x) (3-2) + [4 (3-x)² - 2x (3-2)² ] - 4 (3-x)² Constant term linear inx Quadratic 4(3-2)² - 2x (3-x) = (3-2) (4-22) 2 12 (3-x) + 6 (3-x)² - 4 (3-20)³ 3

Group and Simplify Like terms 12 (3-x) + (-4x) (3-2) + [4 (3-x)² - 2x (3-2)² ] - 4 (3-x)² Constant term linear inx Quadratic 4(3-2)² - 2x (3-x) = (3-2) (4-22) 2 12 (3-x) + 6 (3-x)² - 4 (3-20)³ 3

Elementary Algebra

17th Edition

ISBN:9780998625713

Author:Lynn Marecek, MaryAnne Anthony-Smith

Publisher:Lynn Marecek, MaryAnne Anthony-Smith

Chapter6: Polynomials

Section6.6: Divide Polynomials

Problem 6.172TI: Find the quotient: (2x3+8x2+x8)(x+1) .

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Question

Calculus III

May I have an expert explained how the terms were simplified into 6(3-x)^2?

Thank you,

Group
and Simplify Like terms
12 (3-x) + (-4x) (3-2) + [4 (3-x)² - 2x (3-2)² ] - 4 (3-x)²
Constant term
linear inx
Quadratic
4(3-2)² - 2x (3-x) = (3-2) (4-22)
2
12 (3-x) + 6 (3-x)² - 4 (3-20)³
3

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