4 The flux of the curl of the vector field F(x, y, z) , xz — ze³², xyz), (x, y, z) € = = (xy + e¯v², xz = R³ through the surface S = {(x, y, z) = R³ : (x+3)² + y²+ z² = 27, x > 0} oriented such that its normal vector has a positive second component, equals: (A) -27π (B) 0 18π (D) 27π
4 The flux of the curl of the vector field F(x, y, z) , xz — ze³², xyz), (x, y, z) € = = (xy + e¯v², xz = R³ through the surface S = {(x, y, z) = R³ : (x+3)² + y²+ z² = 27, x > 0} oriented such that its normal vector has a positive second component, equals: (A) -27π (B) 0 18π (D) 27π
Algebra and Trigonometry (MindTap Course List)
4th Edition
ISBN:9781305071742
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter9: Vectors In Two And Three Dimensions
Section9.FOM: Focus On Modeling: Vectors Fields
Problem 11P
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I circled the correct, could you explain using stoke
![4 The flux of the curl of the vector field F(x, y, z)
, xz — ze³², xyz), (x, y, z) €
=
= (xy + e¯v², xz
=
R³ through the surface S = {(x, y, z) = R³ : (x+3)² + y²+ z² = 27, x > 0} oriented such
that its normal vector has a positive second component, equals:
(A) -27π
(B) 0
18π
(D) 27π](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6099d21a-e15a-47f8-adbb-0c871c33581f%2Fed6401bc-1d82-48be-811d-888197a7e4c2%2Fkpu8r6_processed.png&w=3840&q=75)
Transcribed Image Text:4 The flux of the curl of the vector field F(x, y, z)
, xz — ze³², xyz), (x, y, z) €
=
= (xy + e¯v², xz
=
R³ through the surface S = {(x, y, z) = R³ : (x+3)² + y²+ z² = 27, x > 0} oriented such
that its normal vector has a positive second component, equals:
(A) -27π
(B) 0
18π
(D) 27π
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