Interpretation:
The structure of the compound using given spectroscopic data is to be elucidated.
Concept introduction:
NMR data indicates the number and type of protons or carbons present in a compound based on the number of signals obtained in
Mass spectra of a compound indicate the molecular ion peak which gives the molecular mass of the compound.
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Organic Chemistry
- Given here are 1H-NMR and 13C-NMR spectral data for two compounds. Each shows strong, sharp absorption between 1700 and 1720 cm-1 and strong, broad absorption over the region 2500–3000 cm-1. Propose a structural formula for compound.arrow_forwardThymol (molecular formula C10H14O) is the major component of the oil ofthyme. Thymol shows IR absorptions at 3500–3200, 3150–2850, 1621, and1585 cm−1. The 1H NMR spectrum of thymol is given below. Propose apossible structure for thymol.arrow_forward3. Propose a structure for an organic compound with molecular formula C3H1404 given the following 'H NMR and IR spectra. Draw the structure only, no need to interpret the spectra. 1H NMR Spectrum IR Spectrum Triplet Singlet d (6H) 8 (4H) 8 (4H) 1740 cm1 Quartetarrow_forward
- An unknown compound has a molecular formula of C,H,O. Its IR spectrum shows prominent absorptions at 2980, 2960, and 1718 cm . It exhibits the following signals in its H NMR spectrum (ppm): 1.06 (triplet, 3H), 2.12 (singlet, 3H), 2.45 (quartet, 2H); and the following signals in its ¹3C NMR spectrum ( ppm): 7.6, 29.5, 36.8, 208.8. Draw the structure of the unknown compound. Click and drag to start drawing a structure. 0 X 0:0arrow_forwardThe 1H-NMR spectrum of Compound C shows five signals – δ 2.38 (1H, dt), 2.72 (1H, dt), 5.34 (1H, t), 5.49 (2H, ddd), 6.27 (2H, dd) ppm. Its 13C-NMR spectrum has four signals – δ 26, 58, 127, 129 ppm. In the compound’s mass spectrum, the M+1 peak appears at m/z = 115. An M+2 peak, whose intensity is roughly one-third that of the M+1 peak, also appears. Suggest a structure for this compound.arrow_forwardAcid-catalyzed hydrolysis of HOCH2CH2C(CH3)2CN forms compound A (C6H10O2). A shows a strong peak in its IR spectrum at 1770 cm-1 and the following signals in its 1H NMR spectrum: 1.27 (singlet, 6 H), 2.12 (triplet, 2 H), and 4.26 (triplet, 2 H) ppm. Draw the structure for A and give a stepwise mechanism that accounts for its formation.arrow_forward
- This compound, (C10H1002), shows strong, sharp absorption between 1700 and 1720 cm, and strong, broad absorption over the region 2500- 3000 cm. Given this information and the following NMR data, please draw the structure of the compound in the box below. H-NMR: 2.34 ppm, s(3H); 6.38 ppm, d(1H); 7.18 ppm, d(1H); 7.44 ppm, d(2H); 7.56 ppm, d(2H); 12.0, s(1H) 19C-NMR: 167.82; 143.82; 139.96; 131.45; 129.37; 127.83; 111.89; 21.13arrow_forwardPlease sol;;;!!!!:??arrow_forwardA solution of acetone [(CH3)2C=O] in ethanol (CH3CH2OH) in the presence of a trace of acid was allowed to stand for several days, and a new compound of molecular formula C7H16O2 was formed. The IR spectrum showed only one major peak in the functional group region around 3000 cm−1, and the 1H NMR spectrum is given here. What is the structure of the product?arrow_forward
- Phenacetin is an analgesic compound having molecular formula C10H13NO2. Once a common component in over-the-counter pain relievers such as APC (aspirin, phenacetin, caffeine), phenacetin is no longer used because of its liver toxicity. Deduce the structure of phenacetin from its 1H NMR and IR spectra.arrow_forward35 please provide the sketal structure from the mass spec chartarrow_forwardUse the 1H NMR and IR data to determine the structure of each compound.arrow_forward
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