Computer Organization and Design MIPS Edition, Fifth Edition: The Hardware/Software Interface (The Morgan Kaufmann Series in Computer Architecture and Design)
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Chapter B, Problem 40E

Explanation of Solution

Truth table:

Present stateNext stateRequired input
Q1Q2Q3Q1Q2Q3d1d2d3
000001001
001011011
011010010
010110110
110111111
111101101
101100100
100000000

Explanation:

  • The above table describes about the 3-bit gray code generator using D-flip flop with the expected gray code inputs d1, d2 and d3 and their calculated values Q=0 and Q’=0.
  • If Q=0 and Q’=1 then, the input is 1.
  • If Q=1 and Q’=0 then, the input is 0.
  • If Q=1 and Q’=1 then, the input is 1.

The above block diagram describes about the 3-bit gray code counter using D-flip flop with the expected gray code inputs d1, d2 and d3. and their calculated values Q=0 and Q’=0.

The logical equation for the inputs d1, d2 and d3 from the above table can be calculated as follows

d1=Q1¯Q2Q3¯+Q1Q2Q3¯+Q1Q2Q3+Q1Q2¯Q3=Q2Q3¯(Q1¯Q1)+Q1Q3(Q2Q2¯)=Q2Q3¯+Q1Q3

d2=Q1¯Q2¯Q3+Q1¯Q2Q3+Q1¯Q2Q3¯+Q1Q2Q3¯=Q1¯Q3(

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