Chapter 9.7, Problem 6OE

To determine

To express: the equations with three-digit number.

Answer to Problem 6OE

The value of 3-digit number is $h+t+u=20$ .

Explanation of Solution

Given information:

A three-digit number has hundreds digit h , tens digit t ,and units digit u .

Formula used:

Digit problems are based on our decimal system of numeration.

Step1. The problem asks for the original number.

Step2. Let h = the hundreds digit of the original number.

Let t = the tens digit of the original number.

Let u = the units digit of the original number.

Step3. Use the facts of the problem to write two equations.

Step4. Solve the equations.

Calculation:

Consider ,

Let h = the hundreds digit of the original number.

Let t = the tens digit of the original number.

Let u = the ones digit of the original number.

	Hundreds	Tens	Units	Value
Original number	$h$	$$ t	$u$	$\begin{array}{l}=h(100)+t(10)+u(1)\\ =100h+10t+u\end{array}$

Therefore, Sum of the digits of the original number:-

  $h+t+u=20$

Hence, the value of 3-digit is $h+t+u=20$ .