Algebra: Structure And Method, Book 1
(REV)00 Edition
ISBN: 9780395977224
Author: Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher: McDougal Littell
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Question
Chapter 9.7, Problem 12P
To determine
To solve: the system of equations in two variables.
Expert Solution & Answer
Answer to Problem 12P
The age of Cecilia is 30 years old now and age of Joe is 54 years old now.
Explanation of Solution
Given information:
Cecilia is 24 years younger than Joe. Six years ago she was half as old as he was.
Formula used:
Age problem.
Step1. The problem asks for the Bob’s age and Claire’s age now.
Step2. Let b = the Cecilia’s age now.
Let c = the Joe‘s age now.
Step3. Use the facts of the problem to write two equations.
Step4. Solve the equations.
Calculation:
Consider ,
Let b = the Cecilia’s age now.
Let c = the Joe’s age now.
| Age | Six year ago |
| Cecilia | b−6 |
| Joe | c−6 |
According to the equation,
=c=b+24 (i)
Also,
=(c−6)=2(b−6)=c−6=2b−12=c−6−2b+12=0=c−2b+6=0 (ii)
Substituting equation (i) in (ii)
=c−2b+6=0=(b+24)−2b+6=0=b+24−2b+6=0=−b+30=0=b=30
Putting value of c in equation (i) we get,
=c=30+24=c=54
Hence, the age of Cecilia is 30 years old now and age of Joe is 54 years old now.
Chapter 9 Solutions
Algebra: Structure And Method, Book 1
Ch. 9.1 - Prob. 1OECh. 9.1 - Prob. 2OECh. 9.1 - Prob. 3OECh. 9.1 - Prob. 4OECh. 9.1 - Prob. 5OECh. 9.1 - Prob. 6OECh. 9.1 - Prob. 7OECh. 9.1 - Prob. 8OECh. 9.1 - Prob. 9OECh. 9.1 - Prob. 1WE
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Prob. 5PCh. 9.6 - Prob. 6PCh. 9.6 - Prob. 7PCh. 9.6 - Prob. 8PCh. 9.6 - Prob. 9PCh. 9.6 - Prob. 10PCh. 9.6 - Prob. 11PCh. 9.6 - Prob. 12PCh. 9.6 - Prob. 13PCh. 9.6 - Prob. 14PCh. 9.6 - Prob. 15PCh. 9.6 - Prob. 16PCh. 9.6 - Prob. 17PCh. 9.6 - Prob. 18PCh. 9.6 - Prob. 19PCh. 9.6 - Prob. 20PCh. 9.6 - Prob. 21PCh. 9.6 - Prob. 22PCh. 9.6 - Prob. 23PCh. 9.6 - Prob. 1MRECh. 9.6 - Prob. 2MRECh. 9.6 - Prob. 3MRECh. 9.6 - Prob. 4MRECh. 9.6 - Prob. 5MRECh. 9.6 - Prob. 6MRECh. 9.6 - Prob. 7MRECh. 9.6 - Prob. 8MRECh. 9.6 - Prob. 9MRECh. 9.7 - Prob. 1OECh. 9.7 - Prob. 2OECh. 9.7 - Prob. 3OECh. 9.7 - Prob. 4OECh. 9.7 - Prob. 5OECh. 9.7 - Prob. 6OECh. 9.7 - Prob. 7OECh. 9.7 - Prob. 8OECh. 9.7 - Prob. 9OECh. 9.7 - Prob. 10OECh. 9.7 - Prob. 11OECh. 9.7 - Prob. 12OECh. 9.7 - Prob. 13OECh. 9.7 - Prob. 14OECh. 9.7 - Prob. 15OECh. 9.7 - Prob. 16OECh. 9.7 - Prob. 17OECh. 9.7 - Prob. 18OECh. 9.7 - Prob. 19OECh. 9.7 - Prob. 20OECh. 9.7 - Prob. 21OECh. 9.7 - Prob. 22OECh. 9.7 - Prob. 1PCh. 9.7 - Prob. 2PCh. 9.7 - Prob. 3PCh. 9.7 - Prob. 4PCh. 9.7 - Prob. 5PCh. 9.7 - Prob. 6PCh. 9.7 - Prob. 7PCh. 9.7 - Prob. 8PCh. 9.7 - Prob. 9PCh. 9.7 - Prob. 10PCh. 9.7 - Prob. 11PCh. 9.7 - Prob. 12PCh. 9.7 - Prob. 13PCh. 9.7 - Prob. 14PCh. 9.7 - Prob. 15PCh. 9.7 - Prob. 16PCh. 9.7 - Prob. 17PCh. 9.7 - Prob. 18PCh. 9.7 - Prob. 19PCh. 9.7 - Prob. 20PCh. 9.7 - Prob. 21PCh. 9.7 - Prob. 22PCh. 9.7 - Prob. 23PCh. 9.7 - Prob. 24PCh. 9.7 - Prob. 25PCh. 9.7 - Prob. 26PCh. 9.7 - Prob. 27PCh. 9.7 - Prob. 28PCh. 9.7 - Prob. 29PCh. 9.7 - Prob. 30PCh. 9.7 - Prob. 31PCh. 9.7 - Prob. 32PCh. 9.7 - Prob. 33PCh. 9.7 - Prob. 34PCh. 9.7 - Prob. 1MRECh. 9.7 - Prob. 2MRECh. 9.7 - Prob. 3MRECh. 9.7 - Prob. 4MRECh. 9.7 - Prob. 5MRECh. 9.7 - Prob. 6MRECh. 9.7 - Prob. 7MRECh. 9.7 - Prob. 8MRECh. 9.7 - Prob. 9MRECh. 9.7 - Prob. 10MRECh. 9.7 - Prob. 11MRECh. 9.7 - Prob. 12MRECh. 9.7 - Prob. 1STCh. 9.7 - Prob. 2STCh. 9.7 - Prob. 3STCh. 9.7 - Prob. 4STCh. 9 - Prob. 1CRCh. 9 - Prob. 2CRCh. 9 - Prob. 3CRCh. 9 - Prob. 4CRCh. 9 - Prob. 5CRCh. 9 - 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