Algebra: Structure And Method, Book 1

(REV)00 Edition

ISBN: 9780395977224

Author: Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Publisher: McDougal Littell

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Question

Chapter 9.5, Problem 46WE

To determine

To find: The value of x,y and z by using multiplication with the addition-or-subtraction method.

Expert Solution & Answer

Answer to Problem 46WE

The the value of x is −1 , the value of y is 2 , and the value of z is 3 .

Explanation of Solution

Given information:

The given equations are,

6x+4y−z=−7−5x+6y+2z=143x−2y−3z=−13

Calculation:

Calculate the equations,

6x+4y−z=−7.................................(1)−5x+6y+2z=14..................................(2)3x−2y−3z=−13..............................(3)

Multiply by 2 in equation (3)

2(3x−2y−3z)=−136x−4y−6z=−26...............................(4)

Add equation (1)&(4) .

6x+4y−z=−76x−4y−6z=−26

12x −7z =−33

Solve the result,

12x−7z=−33.............................(5)

Multiply by 3 in equation (3)

3(3x−2y−3z)=−13(3)9x−6y−9z=−39..............................(6)

Add equation (2)&(6) .

−5x+6y+2z=149x−6y−9z=−39

4x −7z = −25

Solve the result,

4x−7z=−25..............................(7)

Subtract equation (5) from equation (7) .

4x−7z=−2512x−7z=−33− + +

−8x = 8

Solve the result,

x=−1

Substitute the value of x in equation (5)or(7) to get z .

12x−7z=−3312(−1)−7z=−33−7z=−33+12z=3

Substitute the value of x&z in original equation get y .

6x+4y−z=−76(−1)+y−3=−7−6+y−3=−7y=2

Therefore,

x=−1y=2z=3

Therefore, the value of x is −1 , the value of y is 2 , and the value of z is 3 .

Chapter 9.5, Problem 45WE

Chapter 9.5, Problem 1MP

Chapter 9 Solutions

Algebra: Structure And Method, Book 1

Ch. 9.1 - Prob. 1OE Ch. 9.1 - Prob. 2OE Ch. 9.1 - Prob. 3OE Ch. 9.1 - Prob. 4OE Ch. 9.1 - Prob. 5OE Ch. 9.1 - Prob. 6OE Ch. 9.1 - Prob. 7OE Ch. 9.1 - Prob. 8OE Ch. 9.1 - Prob. 9OE Ch. 9.1 - Prob. 1WE

Ch. 9.1 - Prob. 2WE Ch. 9.1 - Prob. 3WE Ch. 9.1 - Prob. 4WE Ch. 9.1 - Prob. 5WE Ch. 9.1 - Prob. 6WE Ch. 9.1 - Prob. 7WE Ch. 9.1 - Prob. 8WE Ch. 9.1 - Prob. 9WE Ch. 9.1 - Prob. 10WE Ch. 9.1 - Prob. 11WE Ch. 9.1 - Prob. 12WE Ch. 9.1 - Prob. 13WE Ch. 9.1 - Prob. 14WE Ch. 9.1 - Prob. 15WE Ch. 9.1 - Prob. 16WE Ch. 9.1 - Prob. 17WE Ch. 9.1 - Prob. 18WE Ch. 9.1 - Prob. 19WE Ch. 9.1 - Prob. 20WE Ch. 9.1 - Prob. 21WE Ch. 9.1 - Prob. 22WE Ch. 9.1 - Prob. 23WE Ch. 9.1 - Prob. 24WE Ch. 9.1 - Prob. 1MRE Ch. 9.1 - Prob. 2MRE Ch. 9.1 - Prob. 3MRE Ch. 9.1 - Prob. 4MRE Ch. 9.1 - Prob. 5MRE Ch. 9.1 - Prob. 6MRE Ch. 9.1 - Prob. 1CE Ch. 9.1 - Prob. 2CE Ch. 9.1 - Prob. 3CE Ch. 9.1 - Prob. 4CE Ch. 9.2 - Prob. 1OE Ch. 9.2 - Prob. 2OE Ch. 9.2 - Prob. 3OE Ch. 9.2 - Prob. 4OE Ch. 9.2 - Prob. 5OE Ch. 9.2 - Prob. 6OE Ch. 9.2 - Prob. 7OE Ch. 9.2 - Prob. 8OE Ch. 9.2 - Prob. 9OE Ch. 9.2 - Prob. 10OE Ch. 9.2 - Prob. 11OE Ch. 9.2 - Prob. 12OE Ch. 9.2 - Prob. 1WE Ch. 9.2 - Prob. 2WE Ch. 9.2 - Prob. 3WE Ch. 9.2 - Prob. 4WE Ch. 9.2 - Prob. 5WE Ch. 9.2 - Prob. 6WE Ch. 9.2 - Prob. 7WE Ch. 9.2 - Prob. 8WE Ch. 9.2 - Prob. 9WE Ch. 9.2 - Prob. 10WE Ch. 9.2 - Prob. 11WE Ch. 9.2 - Prob. 12WE Ch. 9.2 - Prob. 13WE Ch. 9.2 - Prob. 14WE Ch. 9.2 - Prob. 15WE Ch. 9.2 - Prob. 16WE Ch. 9.2 - Prob. 17WE Ch. 9.2 - Prob. 18WE Ch. 9.2 - Prob. 19WE Ch. 9.2 - Prob. 20WE Ch. 9.2 - Prob. 21WE Ch. 9.2 - Prob. 22WE Ch. 9.2 - Prob. 23WE Ch. 9.2 - Prob. 24WE Ch. 9.2 - Prob. 25WE Ch. 9.2 - Prob. 26WE Ch. 9.2 - Prob. 27WE Ch. 9.2 - Prob. 28WE Ch. 9.2 - Prob. 29WE Ch. 9.2 - Prob. 30WE Ch. 9.2 - Prob. 31WE Ch. 9.2 - Prob. 32WE Ch. 9.2 - Prob. 33WE Ch. 9.2 - Prob. 34WE Ch. 9.2 - Prob. 35WE Ch. 9.2 - Prob. 36WE Ch. 9.2 - Prob. 37WE Ch. 9.2 - Prob. 38WE Ch. 9.2 - Prob. 39WE Ch. 9.2 - Prob. 40WE Ch. 9.2 - Prob. 41WE Ch. 9.2 - Prob. 1MRE Ch. 9.2 - Prob. 2MRE Ch. 9.2 - Prob. 3MRE Ch. 9.2 - Prob. 4MRE Ch. 9.2 - Prob. 5MRE Ch. 9.2 - Prob. 6MRE Ch. 9.2 - Prob. 7MRE Ch. 9.2 - Prob. 8MRE Ch. 9.2 - Prob. 9MRE Ch. 9.2 - Prob. 10MRE Ch. 9.2 - Prob. 11MRE Ch. 9.2 - 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