(a) Answer The solution of the given system to the nearest half units is ( 4 , − 1 ) . Explanation Given: The given equations are: 7 x + 5 y = 25 … ( 1 ) 2 x − 5 y = 15 … ( 2 ) Calculation: The graph of the given equations is shown below: By using the above graph the solution of the given system to the nearest half units is ( 4 , − 1 ) . (b) To determine To find: The exact solution of the given above system. Answer The exact solution of the given system is ( 4.444 , − 1.222 ) . Explanation To find the exact solution, first, add the given two equations. Then the calculation is given as: 7 x + 5 y + ( 2 x − 5 y ) = 25 + 15 9 x = 40 x = 40 9 = 4.444 Further simplified by substituting the value of x = 4.444 in the equation ( 2 ) as: 2 ( 4.444 ) − 5 y = 15 8.888 − 5 y = 15 − 5 y = 6.112 y = − 1.222 Therefore, the exact solution of the given system is ( 4.444 , − 1.222 ) .

(REV)00 Edition

ISBN: 9780395977224

Author: Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Publisher: McDougal Littell

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Question

Chapter 9.4, Problem 28WE

(a)

To determine

To find: The solution of the given system of equation by using the graph to the nearest half units.

(a)

Expert Solution

Answer to Problem 28WE

The solution of the given system to the nearest half units is (4,−1) .

Explanation of Solution

Given:

The given equations are:

7x+5y=25 …(1)2x−5y=15 … (2)

Calculation:

The graph of the given equations is shown below:

Algebra: Structure And Method, Book 1, Chapter 9.4, Problem 28WE

By using the above graph the solution of the given system to the nearest half units is (4,−1) .

(b)

To determine

To find: The exact solution of the given above system.

(b)

Expert Solution

Answer to Problem 28WE

The exact solution of the given system is (4.444,−1.222) .

Explanation of Solution

To find the exact solution, first, add the given two equations.

Then the calculation is given as:

7x+5y+(2x−5y)=25+159x=40x=409=4.444

Further simplified by substituting the value of x=4.444 in the equation (2) as:

2(4.444)−5y=158.888−5y=15−5y=6.112y=−1.222

Therefore, the exact solution of the given system is (4.444,−1.222) .

Chapter 9.4, Problem 27WE

Chapter 9.4, Problem 29WE

Chapter 9 Solutions

Algebra: Structure And Method, Book 1

Ch. 9.1 - Prob. 1OE Ch. 9.1 - Prob. 2OE Ch. 9.1 - Prob. 3OE Ch. 9.1 - Prob. 4OE Ch. 9.1 - Prob. 5OE Ch. 9.1 - Prob. 6OE Ch. 9.1 - Prob. 7OE Ch. 9.1 - Prob. 8OE Ch. 9.1 - Prob. 9OE Ch. 9.1 - Prob. 1WE

Ch. 9.1 - Prob. 2WE Ch. 9.1 - Prob. 3WE Ch. 9.1 - Prob. 4WE Ch. 9.1 - Prob. 5WE Ch. 9.1 - Prob. 6WE Ch. 9.1 - Prob. 7WE Ch. 9.1 - Prob. 8WE Ch. 9.1 - Prob. 9WE Ch. 9.1 - Prob. 10WE Ch. 9.1 - Prob. 11WE Ch. 9.1 - Prob. 12WE Ch. 9.1 - Prob. 13WE Ch. 9.1 - Prob. 14WE Ch. 9.1 - Prob. 15WE Ch. 9.1 - Prob. 16WE Ch. 9.1 - Prob. 17WE Ch. 9.1 - Prob. 18WE Ch. 9.1 - Prob. 19WE Ch. 9.1 - Prob. 20WE Ch. 9.1 - Prob. 21WE Ch. 9.1 - Prob. 22WE Ch. 9.1 - Prob. 23WE Ch. 9.1 - Prob. 24WE Ch. 9.1 - Prob. 1MRE Ch. 9.1 - Prob. 2MRE Ch. 9.1 - Prob. 3MRE Ch. 9.1 - Prob. 4MRE Ch. 9.1 - Prob. 5MRE Ch. 9.1 - Prob. 6MRE Ch. 9.1 - Prob. 1CE Ch. 9.1 - Prob. 2CE Ch. 9.1 - Prob. 3CE Ch. 9.1 - Prob. 4CE Ch. 9.2 - Prob. 1OE Ch. 9.2 - Prob. 2OE Ch. 9.2 - Prob. 3OE Ch. 9.2 - Prob. 4OE Ch. 9.2 - Prob. 5OE Ch. 9.2 - Prob. 6OE Ch. 9.2 - Prob. 7OE Ch. 9.2 - Prob. 8OE Ch. 9.2 - Prob. 9OE Ch. 9.2 - Prob. 10OE Ch. 9.2 - Prob. 11OE Ch. 9.2 - Prob. 12OE Ch. 9.2 - Prob. 1WE Ch. 9.2 - Prob. 2WE Ch. 9.2 - Prob. 3WE Ch. 9.2 - Prob. 4WE Ch. 9.2 - Prob. 5WE Ch. 9.2 - Prob. 6WE Ch. 9.2 - Prob. 7WE Ch. 9.2 - Prob. 8WE Ch. 9.2 - Prob. 9WE Ch. 9.2 - Prob. 10WE Ch. 9.2 - Prob. 11WE Ch. 9.2 - Prob. 12WE Ch. 9.2 - Prob. 13WE Ch. 9.2 - Prob. 14WE Ch. 9.2 - Prob. 15WE Ch. 9.2 - Prob. 16WE Ch. 9.2 - Prob. 17WE Ch. 9.2 - Prob. 18WE Ch. 9.2 - Prob. 19WE Ch. 9.2 - Prob. 20WE Ch. 9.2 - Prob. 21WE Ch. 9.2 - Prob. 22WE Ch. 9.2 - Prob. 23WE Ch. 9.2 - Prob. 24WE Ch. 9.2 - Prob. 25WE Ch. 9.2 - Prob. 26WE Ch. 9.2 - Prob. 27WE Ch. 9.2 - Prob. 28WE Ch. 9.2 - Prob. 29WE Ch. 9.2 - Prob. 30WE Ch. 9.2 - Prob. 31WE Ch. 9.2 - Prob. 32WE Ch. 9.2 - Prob. 33WE Ch. 9.2 - Prob. 34WE Ch. 9.2 - Prob. 35WE Ch. 9.2 - Prob. 36WE Ch. 9.2 - Prob. 37WE Ch. 9.2 - Prob. 38WE Ch. 9.2 - Prob. 39WE Ch. 9.2 - Prob. 40WE Ch. 9.2 - Prob. 41WE Ch. 9.2 - Prob. 1MRE Ch. 9.2 - Prob. 2MRE Ch. 9.2 - Prob. 3MRE Ch. 9.2 - Prob. 4MRE Ch. 9.2 - Prob. 5MRE Ch. 9.2 - Prob. 6MRE Ch. 9.2 - Prob. 7MRE Ch. 9.2 - Prob. 8MRE Ch. 9.2 - Prob. 9MRE Ch. 9.2 - Prob. 10MRE Ch. 9.2 - Prob. 11MRE Ch. 9.2 - 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