Chapter 9.5, Problem 5P

To determine

To find: The area of rectangle.

Answer to Problem 5P

The area of rectangle is $900\text{sq}\text{.unit}$ .

Explanation of Solution

Given information:

The given length is $5$ more than twice the width.

Perimeter is $130$ .

Calculation:

The length be $x$ and the width be $y$ .

The length of $R$ is $5$ more than the twice the width.

  $x=2y+\mathrm{5............}\left(1\right)$

The perimeter is 130.

  $2\left(x+y\right)=\mathrm{130............}\left(2\right)$

Substitute the value of $x$ from equation $\left(1\right)$ in equation $\left(2\right)$ .

  $\begin{array}{c}2\left(2y+5+y\right)=130\\ 6y+10=130\\ 6y=120\\ y=20\end{array}$

Hence, the width is $20$ unit and length is $45$ unit.

Area of rectangle is $=\text{lenght}\times \text{width}$

  $\begin{array}{c}Area=\text{45}\times \text{20}\\ =\text{900}\text{sq}\text{.unit}\end{array}$

Therefore, the area of rectangle is $900\text{sq}\text{.unit}$ .