Chapter 9.3, Problem 94E

(a)

To determine

To find: the power of the test against this alternative.

Answer to Problem 94E

  $\text{Power =}0.77=77\%$

Explanation of Solution

Given:

  $P\left(\text{Type II error}\right)=0.23$

Calculation:

The power is the complement of the probability of a type II error, therefore the power is

  $\text{Power =1-}P\left(\text{Type II error}\right)=1-0.23=0.77=77\%$

(b)

To determine

To find: the probability of making a Type-I error

Answer to Problem 94E

  $P\left(\text{Type I error}\right)=0.05=5\%$

Explanation of Solution

Given:

  $\alpha =0.05$

Calculation:

The significance level $\alpha$ shows the probability of a type I error.

  $P\left(\text{Type I error}\right)=\alpha =0.05=5\%$