Explanation The below figure shows the T − s diagram of the process. Figure-(1) Write the expression for the specific enthalpy at state 1. h 1 = h a + V a 2 2 (I) Here, the specific enthalpy at state 1 is h 1 , the specific volume at state a is V a and the specific enthalpy at state a is h a . Write the expression for the pressure at state 1. p 1 = ( p r 1 p r a ) p a (II) Here, the pressure at state 1 is p 1 , the pressure at state a is p a , the reduced pressure at state 1 is p r 1 and the reduced pressure at state a is p r a . Write the expression for the saturated pressure at state 2. p r 2 s = ( p 2 p 1 ) p r 1 (III) Here, the pressure at state 2 is p 2 and the saturated pressure at state a is p r 2 s . Write the expression for the specific enthalpy in terms of compressor efficiency at state 2. h 2 = h 1 + ( h 2 s − h 1 η c ) (IV) Here, the compressor efficiency is η c , the specific enthalpy at state 2 is h 2 and the saturated specific enthalpy at state 2 is h 2 s . Write the expression for the specific enthalpy at state 4. h 4 = h 3 − η t ( h 3 − h 4 s ) (V) Here, the specific enthalpy at state 4 is h 4 and the specific enthalpy at state is h 3 . Write the expression for the saturated specific enthalpy in terms of turbine efficiency at state 4. h 4 s = h 3 − ( h 2 − h 1 η t ) (VI) Here, the turbine efficiency is η t , the saturated specific enthalpy at state 4 is h 4 s . Write the expression for the pressure at state 4. p 4 = ( p r 4 s p r 3 ) p 3 (VII) Here, the pressure at state 4 is p 4 , the pressure at state 3 is p 3 , the reduced pressure at state 3 is p r 3 and the saturated reduced pressure at state 4 is p r 4 s . Write the expression for the reduced pressure at state 5. p r 5 = ( p 5 p 4 ) p r 4 (VIII) Here, the pressure at state 5 is p 5 , the reduced pressure at state 5 is p r 5 and the reduced pressure at state 4 is p r 4 . Write the expression for the pressure at state 4. p 4 = ( p r 4 s p r 3 ) p 3 (IX) Here, the pressure at state 4 is p 4 , the pressure at state 3 is p 3 , the reduced pressure at state 3 is p r 3 and the saturated reduced pressure at state 4 is p r 4 s . Write the expression for the velocity at the nozzle exit. V 5 = 2 ( h 4 − h 5 s ) (X) Here, the velocity at the nozzle exit is V 5 . Write the expression for force developed. F x = m ( V 5 − V a ) (XI) Here, the initial velocity is V a . Write the expression for thrust force. F t h r u s t = − F x (XII) Conclusion: Refer to table A-22E “ideal gas properties of air” to obtain the specific enthalpy and reduced pressure at temperature T a = 420 ° R as 100.32 Btu / lb and 0.5760 . Substitute 100.32 Btu / lb for h a , 750 ft / s for V a in Equation (I). h 1 = ( 100.32 Btu / lb ) + ( 750 ft / s ) 2 2 = ( 100.32 Btu / lb ) + { 281250 ( ft / s ) 2 ( 1 lbf 32.2 lb ⋅ ft / s 2 ) ( 1 Btu 778 ft ⋅ lbf ) } = 111.5468 Btu / lb ≈ 111.55 Btu / lb Refer to table A-22E “ideal gas properties of air” to obtain the reduced pressure at specific enthalpy h 1 = 111.55 Btu / lb as 0.8349 . Substitute 0.8349 for p r 1 , 0.5760 for p r a and 9 lbf / in 2 for p a in Equation (II). p 1 = ( 0.8349 0.5760 ) ( 9 lbf / in 2 ) = 1.4494 ( 9 lbf / in 2 ) ≈ 13.05 lbf / in 2 Substitute 12 for p 2 p 1 and 0.8349 for p r 1 in Equation (III). p r 2 s = ( 0.8349 ) ( 12 ) = 10.01 Refer to table A-22E “ideal gas properties of air” to obtain the saturated specific enthalpy at reduced pressure p r 2 s = 10.01 as 227.29 Btu / lb . Substitute 227.29 Btu / lb for h 2 s , 111.55 Btu / lb 254.22 kJ / kg for h 1 and 0.88 for η c in Equation (IV). h 2 = 111.55 Btu / lb + ( 227.29 Btu / lb − 111.55 Btu / lb 0

8th Edition

ISBN: 9781119391630

Author: MORAN

Publisher: WILEY

See similar textbooks

Videos

Question

Chapter 9.14, Problem 105P

To determine

The thrust force developed by the engine.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 9.14, Problem 104P

Chapter 9.14, Problem 106P

Students have asked these similar questions

How do i solve this problem?

Q4/ A compressor is driven motor by mean of a flat belt of thickness 10 mm and a width of 250 mm. The motor pulley is 300 mm diameter and run at 900 rpm and the compressor pulley is 1500 mm diameter. The shaft center distance is 1.5 m. The angle of contact of the smaller pulley is 220° and on the larger pulley is 270°. The coefficient of friction between the belt and the small pulley is 0.3, and between the belt and the large pulley is 0.25. The maximum allowable belt stress is 2 MPa and the belt density is 970 kg/m³. (a) What is the power capacity of the drive and (b) If the small pulley replaced by V-grooved pulley of diameter 300 mm, grooved angle of 34° and the coefficient of friction between belt and grooved pulley is 0.35. What will be the power capacity in this case, assuming that the diameter of the large pulley remain the same of 1500 mm.

You are tasked with designing a power drive system to transmit power between a motor and a conveyor belt in a manufacturing facility as illustrated in figure. The design must ensure efficient power transmission, reliability, and safety. Given the following specifications and constraints, design drive system for this application: Specifications: Motor Power: The electric motor provides 10 kW of power at 1,500 RPM. Output Speed: The output shaft should rotate at 150 rpm. Design Decisions: Transmission ratio: Determine the necessary drive ratio for the system. Shaft Diameter: Design the shafts for both the motor and the conveyor end. Material Selection: Choose appropriate materials for the gears, shafts. Bearings: Select suitable rolling element bearings. Constraints: Space Limitation: The available space for the gear drive system is limited to a 1-meter-long section. Attribute 4 of CEP Depth of knowledge required Fundamentals-based, first principles analytical approach…

Chapter 9 Solutions

FUND OF ENGINEERING THERMO W/WILEY PLU

Ch. 9.14 - Prob. 1E Ch. 9.14 - Prob. 2E Ch. 9.14 - Prob. 3E Ch. 9.14 - Prob. 4E Ch. 9.14 - Prob. 5E Ch. 9.14 - 6. What is the purpose of a rear diffuser on a...Ch. 9.14 - 7. What is the meaning of the octane rating that...Ch. 9.14 - Prob. 8E Ch. 9.14 - Prob. 9E Ch. 9.14 - 10. What is the purpose of the gas turbine–powered...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.