Chapter 9.1, Problem 9PP

To determine

Angular velocity and angular impulse of the wheel.

Answer to Problem 9PP

  $0.1884\text{ kg}\cdot \text{m/s}$

Explanation of Solution

Given:

Wheel rotates with a speed of 5 rev/s

Moment of inertia $I=0.06{\text{ kg-m}}^2$

Formula Used:

Angular impulse is given by:

  $L=I\omega$

Where, Iis the moment of inertia and $\omega$ is angular speed.

Calculations:

Angular velocity of wheel in rad/s will be equal to:

  $\begin{array}{c}\omega =2\pi \times 5\\ =10\pi \\ =10\times 3.14\\ =31.4\text{ rad/s}\end{array}$

Angular impulse is given by:

  $\begin{array}{c}L=I\omega \\ =0.06\times 3.14\\ =0.1884\text{ kg}\cdot \text{m/s}\end{array}$

Conclusion:

Therefore, angular velocity of $31.4\text{ rad/s}$ and angular impulse is equal to $0.1884\text{ kg}\cdot \text{m/s}$ .