Chapter 9, Problem 41A

To determine

The time for which the Rocio’s club was in contact with the ball.

Answer to Problem 41A

  $0.0132\text{s}$

Explanation of Solution

Given:

The mass of the golf ball that was strike by the Rocio, $m=0.058\text{kg}$

The force with which the ball was strike, $F=272\text{N}$

The velocity of the ball due to the exerted force, $v=62.0\text{m/s}$

Formula used:

Momentum of an object of mass m and moving with velocity v is given by,

  $p=mv$

Impulse on an object is equal to the change in momentum of an object,

  $\text{Impulse = }F\Delta t=p_f-p_i$

where $F$ is the applied force for time $\Delta t$ , $p_f$ is the final momentum, $p_i$ is the initial momentum.

Calculation:

Using the above values in above formula, the time of contact will be,

  $\begin{array}{c}F\Delta t=m\Delta v\\ 272\Delta t=0.058\left(62\right)\\ \Delta t=0.0132\text{s}\end{array}$

Conclusion:

Thus, the time for which the Rocio’s club was in contact with the ball $0.0132\text{s}$ .