Chapter 9, Problem 53A

To determine

The combined momentum of brother and his skateboard if they are moving at $9.50\text{m/s}$ .

Answer to Problem 53A

  $350.55\text{kg}\cdot \text{m/s}$

Explanation of Solution

Given:

The mass of brother, $m_b=35.6\text{kg}$

The mass of skateboard, $m_s=1.3\text{kg}$

Velocity of brother and skateboard, $v=9.50\text{m/s}$

Formula used:

Momentum of an object of mass m and moving with velocity v is given by,

  $p=mv$

Calculation:

Using all the given above formula, the combined mass of brother and his skateboard is,

  $\begin{array}{c}p=\left(m_b+m_s\right)v\\ =\left(35.6+1.3\right)9.50\\ =350.55\text{kg}\cdot \text{m/s}\end{array}$

Conclusion:

Thus, the combined momentum of brother and his skateboard is $350.55\text{kg}\cdot \text{m/s}$ .