ACHIEVE/CHEMICAL PRINCIPLES ACCESS 2TERM
7th Edition
ISBN: 9781319403959
Author: ATKINS
Publisher: MAC HIGHER
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Chapter 9, Problem 9A.13E
Interpretation Introduction
Interpretation:
The element, which readily forms
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Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard
the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
For the decomposition reaction of N2O5(g): 2 N2O5(g) · 4 NO2(g) + O2(g), the following mechanism has been proposed:
N2O5
-> NO2 + NO3_(K1)
NO2 + NO3 →> N2O5 (k-1)
→
NO2 + NO3
→
NO2 + O2 + NO (K2)
NO + N2O5
→ NO2 + NO2 + NO2 (K3)
Give the expression for the acceptable rate.
(A).
d[N₂O]
dt
=
-1
2k,k₂[N205]
k₁+k₂
d[N₂O5]
(B).
dt
=-k₁[N₂O₂] + k₁[NO2][NO3] - k₂[NO2]³
(C).
d[N₂O]
dt
=-k₁[N₂O] + k₁[N205] - K3 [NO] [N205]
(D).
d[N2O5]
=-k₁[NO] - K3[NO] [N₂05]
dt
A 0.10 M solution of acetic acid (CH3COOH, Ka = 1.8 x 10^-5) is titrated with a 0.0250 M solution of magnesium hydroxide (Mg(OH)2). If 10.0 mL of the acid solution is titrated with 20.0 mL of the base solution, what is the pH of the resulting solution?
For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed:
N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3)
→
Give the expression for the acceptable rate.
→
→
(A).
d[N205]
dt
==
2k,k₂[N₂O₂]
k₁+k₁₂
(B).
d[N2O5]
=-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³
dt
(C).
d[N2O5]
=-k₁[N₂O] + k [NO] - k₂[NO] [NO]
d[N2O5]
(D).
=
dt
= -k₁[N2O5] - k¸[NO][N₂05]
dt
Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard
the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
Chapter 9 Solutions
ACHIEVE/CHEMICAL PRINCIPLES ACCESS 2TERM
Ch. 9 - Prob. 9A.1ASTCh. 9 - Prob. 9A.1BSTCh. 9 - Prob. 9A.1ECh. 9 - Prob. 9A.2ECh. 9 - Prob. 9A.3ECh. 9 - Prob. 9A.4ECh. 9 - Prob. 9A.5ECh. 9 - Prob. 9A.6ECh. 9 - Prob. 9A.7ECh. 9 - Prob. 9A.8E
Ch. 9 - Prob. 9A.9ECh. 9 - Prob. 9A.10ECh. 9 - Prob. 9A.11ECh. 9 - Prob. 9A.12ECh. 9 - Prob. 9A.13ECh. 9 - Prob. 9A.14ECh. 9 - Prob. 9B.1ASTCh. 9 - Prob. 9B.1BSTCh. 9 - Prob. 9B.2ASTCh. 9 - Prob. 9B.2BSTCh. 9 - Prob. 9B.1ECh. 9 - Prob. 9B.2ECh. 9 - Prob. 9B.3ECh. 9 - Prob. 9B.4ECh. 9 - Prob. 9B.5ECh. 9 - Prob. 9B.6ECh. 9 - Prob. 9B.7ECh. 9 - Prob. 9B.8ECh. 9 - Prob. 9B.9ECh. 9 - Prob. 9B.10ECh. 9 - Prob. 9B.11ECh. 9 - Prob. 9B.12ECh. 9 - Prob. 9B.13ECh. 9 - Prob. 9B.14ECh. 9 - Prob. 9B.15ECh. 9 - Prob. 9B.16ECh. 9 - Prob. 9C.1ASTCh. 9 - Prob. 9C.1BSTCh. 9 - Prob. 9C.2ASTCh. 9 - Prob. 9C.2BSTCh. 9 - Prob. 9C.3ASTCh. 9 - Prob. 9C.3BSTCh. 9 - Prob. 9C.4ASTCh. 9 - Prob. 9C.4BSTCh. 9 - Prob. 9C.1ECh. 9 - Prob. 9C.2ECh. 9 - Prob. 9C.3ECh. 9 - Prob. 9C.4ECh. 9 - Prob. 9C.5ECh. 9 - Prob. 9C.6ECh. 9 - Prob. 9C.7ECh. 9 - Prob. 9C.8ECh. 9 - Prob. 9C.9ECh. 9 - Prob. 9C.10ECh. 9 - Prob. 9C.11ECh. 9 - Prob. 9C.12ECh. 9 - Prob. 9C.13ECh. 9 - Prob. 9C.14ECh. 9 - Prob. 9C.15ECh. 9 - Prob. 9C.16ECh. 9 - Prob. 9C.17ECh. 9 - Prob. 9C.18ECh. 9 - Prob. 9C.19ECh. 9 - Prob. 9C.20ECh. 9 - Prob. 9D.1ASTCh. 9 - Prob. 9D.1BSTCh. 9 - Prob. 9D.2ASTCh. 9 - Prob. 9D.2BSTCh. 9 - Prob. 9D.3ASTCh. 9 - Prob. 9D.3BSTCh. 9 - Prob. 9D.4ASTCh. 9 - Prob. 9D.4BSTCh. 9 - Prob. 9D.1ECh. 9 - Prob. 9D.2ECh. 9 - Prob. 9D.3ECh. 9 - Prob. 9D.4ECh. 9 - Prob. 9D.5ECh. 9 - Prob. 9D.6ECh. 9 - Prob. 9D.7ECh. 9 - Prob. 9D.8ECh. 9 - Prob. 9D.9ECh. 9 - Prob. 9D.10ECh. 9 - Prob. 9D.11ECh. 9 - Prob. 9D.12ECh. 9 - Prob. 9D.13ECh. 9 - Prob. 9D.14ECh. 9 - Prob. 9D.15ECh. 9 - Prob. 9D.16ECh. 9 - Prob. 9D.17ECh. 9 - Prob. 9D.18ECh. 9 - Prob. 9D.19ECh. 9 - Prob. 9D.20ECh. 9 - Prob. 9D.21ECh. 9 - Prob. 9D.22ECh. 9 - Prob. 9D.23ECh. 9 - Prob. 9D.24ECh. 9 - Prob. 9D.25ECh. 9 - Prob. 9D.26ECh. 9 - Prob. 9D.27ECh. 9 - Prob. 9D.28ECh. 9 - Prob. 9D.29ECh. 9 - Prob. 9D.30ECh. 9 - Prob. 9D.31ECh. 9 - Prob. 9D.32ECh. 9 - Prob. 9D.33ECh. 9 - Prob. 9D.34ECh. 9 - Prob. 9.1ECh. 9 - Prob. 9.2ECh. 9 - Prob. 9.3ECh. 9 - Prob. 9.4ECh. 9 - Prob. 9.5ECh. 9 - Prob. 9.6ECh. 9 - Prob. 9.7ECh. 9 - Prob. 9.8ECh. 9 - Prob. 9.9ECh. 9 - Prob. 9.10ECh. 9 - Prob. 9.11ECh. 9 - Prob. 9.12ECh. 9 - Prob. 9.13ECh. 9 - Prob. 9.14ECh. 9 - Prob. 9.15ECh. 9 - Prob. 9.16ECh. 9 - Prob. 9.17ECh. 9 - Prob. 9.18ECh. 9 - Prob. 9.19ECh. 9 - Prob. 9.20ECh. 9 - Prob. 9.21ECh. 9 - Prob. 9.23ECh. 9 - Prob. 9.25E
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3) → Give the expression for the acceptable rate. → → (A). d[N205] dt == 2k,k₂[N₂O₂] k₁+k₁₂ (B). d[N2O5] =-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³ dt (C). d[N2O5] =-k₁[N₂O] + k [NO] - k₂[NO] [NO] d[N2O5] (D). = dt = -k₁[N2O5] - k¸[NO][N₂05] dt Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.arrow_forwardR lactam or lactone considering as weak acid or weak base and whyarrow_forward81. a. Propose a mechanism for the following reaction: OH CH2=CHCHC=N b. What is the product of the following reaction? HO H₂O N=CCH2CH2CH OH HO CH3CCH=CH2 H₂O C=N 82. Unlike a phosphonium ylide that reacts with an aldehyde or a ketone to form an alkene a sulfonium uliaarrow_forward
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