Concept explainers
(a)
Interpretation:
The type of isomer represented by the pair
Concept Introduction:
Isomers:
The compounds with same molecular formula but differ in the arrangement of the atom are said to be isomers.
Coordination Isomers:
Coordination isomerism arises in compounds containing complex anionic and cationic parts. Hence, there are two complex compounds bound together, one with a negative charge and the other with a positive charge. In coordination isomers, the anion and cation complexes of a coordination compound exchange one or more ligands.
(a)

Answer to Problem 9C.12E
The type of isomer represented by the pair
Explanation of Solution
In this pair of isomers the chloride ligand of the anionic part exchanges its place between another parts of the coordination sphere thus it is a coordination isomer.
(b)
Interpretation:
The type of isomer represented by the pair
Concept Introduction:
Refer to part (a).
(b)

Answer to Problem 9C.12E
The type of isomer represented by the pair
Explanation of Solution
In this pair of isomers the chloride ligand exchanges their place between another parts of the coordination sphere thus it is a coordination isomer.
(c)
Interpretation:
The type of isomer represented by the pair
Concept Introduction:
Linkage isomers:
Linkage isomerism occurs with ambidentate ligands that are capable of coordinating in more than one way.
Example:
(c)

Answer to Problem 9C.12E
The type of isomer represented by the pair
Explanation of Solution
In the isomer
(d)
Interpretation:
The type of isomer represented by the pair
Concept Introduction:
Hydrate Isomers:
Hydrate isomers results from replacement of a coordinated group by a solvent molecule in this case it is a water molecule.
(d)

Answer to Problem 9C.12E
The type of isomer represented by the pair
Explanation of Solution
In this pair of isomers the aqua ion which is bound with central atom is exchanged its place with the bromide ligand which present outside the nucleus. Thus these isomers are hydrate isomers.
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Chapter 9 Solutions
ACHIEVE/CHEMICAL PRINCIPLES ACCESS 2TERM
- Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electrons-pushing arrows for the following reaction or mechanistic step(s).arrow_forwardCurved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. I I I H Select to Add Arrows HCI, CH3CH2OHarrow_forwardCurved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and the follow the arrows to draw the intermediate and product in this reaction or mechanistic step(s).arrow_forward
- Curved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the curved arrows to draw the intermediates and product of the following reaction or mechanistic step(s).arrow_forwardCurved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the arrows to draw the intermediate and the product in this reaction or mechanistic step(s).arrow_forwardLook at the following pairs of structures carefully to identify them as representing a) completely different compounds, b) compounds that are structural isomers of each other, c) compounds that are geometric isomers of each other, d) conformers of the same compound (part of structure rotated around a single bond) or e) the same structure.arrow_forward
- Given 10.0 g of NaOH, what volume of a 0.100 M solution of H2SO4 would be required to exactly react all the NaOH?arrow_forward3.50 g of Li are combined with 3.50 g of N2. What is the maximum mass of Li3N that can be produced? 6 Li + N2 ---> 2 Li3Narrow_forward3.50 g of Li are combined with 3.50 g of N2. What is the maximum mass of Li3N that can be produced? 6 Li + N2 ---> 2 Li3Narrow_forward
- Concentration Trial1 Concentration of iodide solution (mA) 255.8 Concentration of thiosulfate solution (mM) 47.0 Concentration of hydrogen peroxide solution (mM) 110.1 Temperature of iodide solution ('C) 25.0 Volume of iodide solution (1) used (mL) 10.0 Volume of thiosulfate solution (5:03) used (mL) Volume of DI water used (mL) Volume of hydrogen peroxide solution (H₂O₂) used (mL) 1.0 2.5 7.5 Time (s) 16.9 Dark blue Observations Initial concentration of iodide in reaction (mA) Initial concentration of thiosulfate in reaction (mA) Initial concentration of hydrogen peroxide in reaction (mA) Initial Rate (mA's)arrow_forwardDraw the condensed or line-angle structure for an alkene with the formula C5H10. Note: Avoid selecting cis-/trans- isomers in this exercise. Draw two additional condensed or line-angle structures for alkenes with the formula C5H10. Record the name of the isomers in Data Table 1. Repeat steps for 2 cyclic isomers of C5H10arrow_forwardExplain why the following names of the structures are incorrect. CH2CH3 CH3-C=CH-CH2-CH3 a. 2-ethyl-2-pentene CH3 | CH3-CH-CH2-CH=CH2 b. 2-methyl-4-pentenearrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
