Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
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Chapter 9, Problem 9.7.2P
To determine
The flexural strength of the composite section.
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A composite floor system uses formed steel deck of the type shown in Figure . The beams are W18 x 50, and the slab has a total thickness of 41⁄2 inches from top of slab to bottom of deck. The effective slab width is 90 inches, and the span length is 30 feet. The structural steel is A992, and the concrete strength is f,c= 4 ksi. Compute the nominal flexural strength with two 3⁄4-inch 3 31⁄2-inch studs per rib.
=
1. The beam shown is interior exposure and is reinforced with
4-#8 Grade 60 bars. 11"
cover over #3 stirrup, also fy =
60 ksi in the region of the beam where the #8 bars are
developed, these stirrups are at 6" centers. f = 4.5 ksi,
lightweight concrete, no fct splitting tensile strength is given.
#8 bars are epoxy coated.
(1) Find the value for Ktr using ACI 318-22 Equation
(25.4.2.4b)
(2) Find la using ACI 318-22 Equation (25.4.2.4a)
4-#8 GR 60
16 in.
#3 stirrup at
6" on center
24 in
Given the section and plan view of the structural elements (Foundation and Column), estimate the concrete material quantities to be used in construction. There are sixteen (16) - C3F2 in the entire structure. Consider only from the foundation base up to the Natural Ground Level (NGL). The concrete is to have a minimum compressive strength of 3500 psi (24 Mpa).
Chapter 9 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
Ch. 9 - Prob. 9.1.1PCh. 9 - Prob. 9.1.2PCh. 9 - Prob. 9.1.3PCh. 9 - Prob. 9.1.4PCh. 9 - Prob. 9.1.5PCh. 9 - Prob. 9.1.6PCh. 9 - A W1422 acts compositely with a 4-inch-thick floor...Ch. 9 - Prob. 9.2.2PCh. 9 - Prob. 9.3.1PCh. 9 - Prob. 9.3.2P
Ch. 9 - Prob. 9.4.1PCh. 9 - Prob. 9.4.2PCh. 9 - Prob. 9.4.3PCh. 9 - Prob. 9.4.4PCh. 9 - Prob. 9.4.5PCh. 9 - Prob. 9.5.1PCh. 9 - Prob. 9.5.2PCh. 9 - Prob. 9.5.3PCh. 9 - Note For Problems 9.6-1 through 9.6-5, use the...Ch. 9 - Note For Problems 9.6-1 through 9.6-5, use the...Ch. 9 - Note For Problems 9.6-1 through 9.6-5, use the...Ch. 9 - Note For Problems 9.6-1 through 9.6-5, use the...Ch. 9 - Note For Problems 9.6-1 through 9.6-5, use the...Ch. 9 - Prob. 9.7.1PCh. 9 - Prob. 9.7.2PCh. 9 - Prob. 9.7.3PCh. 9 - Prob. 9.7.4PCh. 9 - Prob. 9.8.1PCh. 9 - Prob. 9.8.2PCh. 9 - A beam must be designed to the following...Ch. 9 - Prob. 9.8.4PCh. 9 - Prob. 9.8.5PCh. 9 - Prob. 9.8.6PCh. 9 - Prob. 9.8.7PCh. 9 - Prob. 9.8.8PCh. 9 - Use the composite beam tables and select a W-shape...Ch. 9 - Prob. 9.8.10PCh. 9 - Prob. 9.10.1PCh. 9 - Prob. 9.10.2P
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- Use the composite beam tables and select a W-shape and stud anchors for the following conditions: Span length = 18 6 Beam spacing = 9 ft Total slab thickness = 51 2 in. (the slab and deck combination weighs 57 psf). Lightweight concrete with a unit weight of 115 pcf is used Construction load = 20 psf Partition load = 20 psf Live load = 225 psf Fy=50 ksi and fc=4 ksi A cross section of the formed steel deck is shown in Figure P9.8-9. The maximum live-load deflection cannot exceed L/360 (use a lower-bound moment of inertia). a. Use LRFD. b. User ASD.arrow_forward2. Determine if the composite beam pictured below is adequate for this application (this includes bending, shear, deflection and shear stud limit states). The dead load for this beam is 10 psf plus the weight of the deck, which is made from normal weight concrete. I 5" 5" Normal weight slab fc=4000 psi W24x94 Span length = 30' Service Live Load = 100 psf 3/4" Diameter Shear Connectors 8' o.c. typical Fu=60 ksi (shear connectors)arrow_forwardA composite floor system consists of steel beams supporting a formed steel deck and concrete slab. The deck is shown in Figure P, and the total depth from bottom of deck to top of slab is 61⁄2 inches. Lightweight concrete is used (unit weight =115 pcf), and the 28-day compressive strength is 4 ksi. The deck and slab combination weighs 53 psf. The beams are spaced at 12 feet, and the span length is 40 feet. There is a 20psf construction load, a partition load of 20 psf, other dead load of 10 psf, and a live load of 160 psf. The maximum permissible live-load deflection is Ly/360. Use the composite beam tables and select a W-shape with Fy= 50 ksi. Design the stud anchors. Use partial composite action and a lowerbound moment of inertia. a. Use LRFD. b. Use ASDarrow_forward
- Note: Give me both right solutions with clear steps. urgent pleasearrow_forwardProblem 1. The composite beam shown below carries a cantilevered load of 10 kN. The beam consists of one 30 x 124 mm plate and four 12 x 50 mm plates. They are pinned together at 120 mm intervals with round pins. The pin material has a shear strength of 159 MPa. Compute the minimum acceptable diameter for the pins. O O O O O O O -0 O 0- O 1000 mm Do O -120 mm (typ) O O O P = 10 KN 30 x 124 mm 12 x 50 mm (typ)arrow_forwardPlease give mathematical explanation with answerarrow_forward
- Find the ultimate moment of resistance for the rectangular section reinforced as shown below. material strengths: Concrete Reinforcement Width of section Reinforcement fcu= 30-MPa fy:= 450-MPa b:= 280 mm d:= 510 mm d':= 50-mm 2 A, 2410-mm A's:= 628-mm 2 b A', Hi Asarrow_forwardA reinforced concrete cantilever beam is shown below. The beam cross section is a rectangle, 12 inches deep by 18 inches wide. Material properties are: - Concrete weight: wt = 150 pcf - Concrete compressive strength: f'c = 4000 psi - Concrete tensile strength: f't = 400 psi - Steel tensile strength: fy = 60 ksi - Stirrup consists of #4 bar - Beam is not exposed to weather or in contact with soil. Determine if the beam will crack under its own weight, if its self-weight is 250lb/ft. 10 ft -18" BEAM SECTION beam will crack beam will not crack unknown, not enough information to calculatearrow_forwardA reinforced concrete cantilever beam is shown below. The beam cross section is a rectangle, 12 inches deep by 18 inches wide. Material properties are: - Concrete weight: wt = 150 pcf - Concrete compressive strength: f'c = 4000 psi - Concrete tensile strength: f't= 400 psi - Steel tensile strength: fy = 60 ksi - Stirrup consists of #4 bar - Beam is not exposed to weather or in contact with soil. Calculate the maximum bending moment under the beam self-weight. 10 ft- 8,750 lb-ft 10,250 lb-ft 11,250 lb-ft 11,750 lb-ft 18" BEAM SECTIONarrow_forward
- A simply supported beam is reinforced with 5-p25 mm at the bottom and 2-020 mm at the top of the beam. Concrete covering to centroid of reinforcement is 70 mm at the top and 64 mm at the bottom of the beam. The beam has a gross depth of 450 mm and gross width of 300 mm. fc'= 28 MPa, fy = 415 MPa. Assume bars laid out in single layer. Calculate the following if the limiting tensile steel strain is 0.004 for a ductile failure: Depth of the neutral axis from the extreme concrete compression fiber to the nearest whole number = mm Design strength of the beam section to the nearest whole number = kN -m Maximum service uniform live load over the entire span in addition to a DL = 20 kN/m (including the weight of the beam) if it has a span of 6 m = kN/m (to the nearest whole number)arrow_forwardA rectangular beam has the dimensions (see Figure) b = 12 in., h - 20 in, and d 17 in. and is reinforced with three No. 9 (No. 29) bars so that As - 3.00 in. The concrete compressive strength fe is 4000 psi, and the tensile strength In bending (modulus of rupture) is 475 psi. The yield point of the steel f, is 60,000 psi. Determine the concrete compression stress at the top fiber caused by a bending moment M- 10 ft-kips. 9- 6.78 in, I= 4067 in, Es= 29000000, E = 3600000 17 in. 20 in. 3 #9 bars (A, - 3.00 in.?) 3 in. -12 in- Select one: a. 390 psi b. 1390 psi c. 200 psi d. 250 psiarrow_forwardNote For Problems 9.6-1 through 9.6-5, use the lower-bound moment of inertia for deflection of the composite section. Compute this as illustrated in Example 9.7. 9.6-5 For the beam of Problem 9.4-2. a. Compute the deflections that occur before and after the concrete has cured. b. It the live toad deflection exceeds L360 , select another steel shape using either LRFD or ASD.arrow_forward
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