Explanation Given: A W 16 X 50 composite beam; thickness, t = 4.5 inches; effective width, b = inches; spacing = 10 ft; span length, L = 35 feet. Construction load = 20 psf; live load = 160 psf. The value of f c ' = 4 k s i . DesignationImperial (in x lb/ft) Depthh (in) Widthw (in) Web Thicknesst w (in) Flange Thicknesst f (in) Sectional Area (in 2 ) Weight (lb f /ft) Static Parameters Moment of Inertia Elastic Section Modulus I x (in 4 ) I y (in 4 ) S x (in 3 ) S y (in 3 ) W 16 x 50 16.26 7.070 0.380 0.630 14.7 50 659 37.2 81 10.5 Calculation: Calculate the compressive force in steel as follows: C S = A S F Y Where, the area of steel section is A S and the yield strength of steel is F Y Get the value of A S from properties and dimensions table from part 1 of the manual. A S = 14.7 i n c h e s 2 . C S = 14.7 i n c h e s 2 × 50 K s i C S = 735 K i p s . Computing the strength of composite section. We have the effective flange width as minimum of the two. b = min [ 12 L A B t i n c h e s , 12 L p i n c h e s ] b = min [ 12 × 35 4.5 i n c h e s , 12 × 10 i n c h e s ] b = min [ 93.33 i n c h e s , 120 i n c h e s ] b = 93.33 i n c h e s . The compressive force in concrete is as follows: C C = 0.85 f C ' b t Where, b is the width of the concrete slab, t is the thickness of the concrete beam and f C ' is the compressive strength of the concrete. Substitute the values in the above equation, we get: C C = 0.85 × 4 k s i × 93.33 i n × 4.5 i n C C = 1428 k i p s . The nominal flexural strength of the composite beam as follows: The compressive force in the beam will be the smaller of the compressive force in steel and compressive force of concrete slab. Calculate the compressive force as following below: C = min ( C C , C S ) Where, the compressive force is C, the compressive force of concrete is C C , and the compressive force of steel beam is C S . C = min ( C C , C S ) C = min ( 1428 k i p s , 735 k i p s ) C = 735 k i p s . Therefore, the plastic neutral axis lies in the slab. Calculate the tensile force (T) and compressive force (C) and the position of plastic neutral axis from the top of concrete slab by following formula: C = T 0.85 f C ' a b = A S F y Where, T is the tensile force and a is the position of the neutral axis below the top of concrete slab. As the neutral axis lies in concrete slab, the full area of steel is in tension and the tensile force of concrete below the neutral axis is neglected. Substitute the values in the above equation, we get: 0.85 × 4 k s i × a × 93.33 i n = 735 k i p s a = 735 k i p s 0.85 × 4 k s i × 93.33 i n a = 2.316 i n . Compute the value of Y as following below: y = d 2 + t − a 2 y = 16.26 i n 2 + 4.5 i n − 2.316 i n 2 y = 8.13 + 4.5 − 1.163 y = 11.467 i n . Now, calculate the flexural strength as following: M n = T y Where, M n is the flexural strength and y is the distance of action of tensile force from plastic neutral axis. M n = 735 k i p s × 11.467 i n M n = 8428.245 i n . k i p s M n = 702.35 f t . k i p s Now compute the loads on the beam as follows: Before curing we have, W S = t 12 ( 150 ) L p Where, t is the thickness of the slab, L p is the distance between two adjacent beams To determine (b) To check: Whether the beam satisfies the provisions of AISC or not.

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN: 9781337094740

Author: Segui, William T.

Publisher: Cengage Learning

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Composite Construction

Composite construction is the construction of structures in which two or more materials are used. Regarding structural engineering, composite construction is a construction where two materials are bound together in a technical manner such that both the m…

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Chapter 9, Problem 9.3.2P

To determine

(a)

To check:

If, the beam satisfies the provisions of AISC or not.

To determine

(b)

To check:

Whether the beam satisfies the provisions of AISC or not.

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Chapter 9, Problem 9.3.1P

Chapter 9, Problem 9.4.1P

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Chapter 9 Solutions

Steel Design (Activate Learning with these NEW titles from Engineering!)

Ch. 9 - Prob. 9.1.1P Ch. 9 - Prob. 9.1.2P Ch. 9 - Prob. 9.1.3P Ch. 9 - Prob. 9.1.4P Ch. 9 - Prob. 9.1.5P Ch. 9 - Prob. 9.1.6P Ch. 9 - A W1422 acts compositely with a 4-inch-thick floor...Ch. 9 - Prob. 9.2.2P Ch. 9 - Prob. 9.3.1P Ch. 9 - Prob. 9.3.2P

Ch. 9 - Prob. 9.4.1P Ch. 9 - Prob. 9.4.2P Ch. 9 - Prob. 9.4.3P Ch. 9 - Prob. 9.4.4P Ch. 9 - Prob. 9.4.5P Ch. 9 - Prob. 9.5.1P Ch. 9 - Prob. 9.5.2P Ch. 9 - Prob. 9.5.3P Ch. 9 - Note For Problems 9.6-1 through 9.6-5, use the...Ch. 9 - Note For Problems 9.6-1 through 9.6-5, use the...Ch. 9 - Note For Problems 9.6-1 through 9.6-5, use the...Ch. 9 - Note For Problems 9.6-1 through 9.6-5, use the...Ch. 9 - Note For Problems 9.6-1 through 9.6-5, use the...Ch. 9 - Prob. 9.7.1P Ch. 9 - Prob. 9.7.2P Ch. 9 - Prob. 9.7.3P Ch. 9 - Prob. 9.7.4P Ch. 9 - Prob. 9.8.1P Ch. 9 - Prob. 9.8.2P Ch. 9 - A beam must be designed to the following...Ch. 9 - Prob. 9.8.4P Ch. 9 - Prob. 9.8.5P Ch. 9 - Prob. 9.8.6P Ch. 9 - Prob. 9.8.7P Ch. 9 - Prob. 9.8.8P Ch. 9 - Use the composite beam tables and select a W-shape...Ch. 9 - Prob. 9.8.10P Ch. 9 - Prob. 9.10.1P Ch. 9 - Prob. 9.10.2P

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