Introduction To Health Physics
5th Edition
ISBN: 9780071835275
Author: Johnson, Thomas E. (thomas Edward), Cember, Herman.
Publisher: Mcgraw-hill Education,
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Chapter 9, Problem 9.3P
To determine
Sample net count rate and95 % Confidence interval.
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ON
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2.75 MeV
0.511 MeV
0.511 MeV
B, E= 1.73 MeV
Eave = 0.721 Mev
O MeV
The (effective) dose to a patient can be measured in milli-Serverts (mSv) or expressed as the time taken to receive the equivalent dose from background radiation. A certain radiograph gives a 1.232 mSv dose which is equivalent to a background radiation dose of 32 weeks.a)How many days in 32 weeks? Give your answer as a whole number.
b)Using the information for the radiograph in this question, calculate the UK daily background dose (in mSv/day). Give your answer to 5 decimal places and use it to this accuracy, if needed in subsequent calculations.
c)Another radiograph has a 0.0054 mSv dose. Work out the equivalent background dose (in days) for this radiograph. Give your answer to 2 decimal places and use it to this accuracy in any subsequent calculations.
d)How many hours is the number of days in part c) equivalent to? Give your answer to 2 decimal places.
A sample counted for 10 minutes resulted in 1,000 counts. The background count was 250
counts over a 10 minute period. Assuming negligible radioactive decay of the sample during
counting, the net counting rate in counts per minute and the standard deviation are
approximately:
a. 750±35 cpm
b. 75±10 cpm
C. 75+3.5 cpm
d. 85±5.5 cpm
e. 8±6 cpm
Chapter 9 Solutions
Introduction To Health Physics
Ch. 9 - Prob. 9.1PCh. 9 - Prob. 9.2PCh. 9 - Prob. 9.3PCh. 9 - Prob. 9.4PCh. 9 - Prob. 9.5PCh. 9 - Prob. 9.6PCh. 9 - Prob. 9.7PCh. 9 - Prob. 9.8PCh. 9 - Prob. 9.9PCh. 9 - Prob. 9.10P
Ch. 9 - Prob. 9.11PCh. 9 - Prob. 9.12PCh. 9 - Prob. 9.13PCh. 9 - A counting system has a background of 360 counts...Ch. 9 - Prob. 9.15PCh. 9 - Prob. 9.16PCh. 9 - Prob. 9.17PCh. 9 - Prob. 9.18PCh. 9 - Prob. 9.19PCh. 9 - Prob. 9.20PCh. 9 - Prob. 9.21PCh. 9 - Prob. 9.22PCh. 9 - Prob. 9.23PCh. 9 - Prob. 9.24PCh. 9 - Prob. 9.25PCh. 9 - Prob. 9.26PCh. 9 - Prob. 9.27PCh. 9 - Prob. 9.28PCh. 9 - Prob. 9.29PCh. 9 - Prob. 9.31PCh. 9 - Prob. 9.33PCh. 9 - Prob. 9.34PCh. 9 - Prob. 9.35PCh. 9 - Prob. 9.38PCh. 9 - Prob. 9.39PCh. 9 - Prob. 9.44P
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- A Geiger counter measures 750 counts in 5.0 min. How long would you want to count to get a relative error of 1%?arrow_forwardIf the dose rate from a sample of Ra-223 was found to be 5.0 x 10-5 mSv per hour at 1.8 metres, calculate the dose rate at 4.8 metres. Show your calculations. Give your answer to two significant figures.arrow_forwardA cancerous tumour is exposed to an a-emitter with an RBE of 16. What absorbed dose, in Gy, is needed to give the tumour an effective dose of 64 Sv? Report your final answer rounded to two significant digits. Your Answer: Answer unitsarrow_forward
- The dosage of technetium-99m for a lung scan is 20. µCi /kg of body mass. How many millicuries of technetium-99m should be given to a 49 kg person (1 mCi = 1000uCi)? Suppose a person absorbed 46 mrad of alpha radiation.What would be the equivalent dose in millirems?arrow_forwardThe radionuclide 32P (T1/2 = 14.28 d) is often used as a tracer to follow the course of biochemical reactions involving phosphorus. (a) If the counting rate in a particular experimental setup is initially 3050 counts/s, how much time will the rate take to fall to 170 counts/s? (b) A solution containing 32P is fed to the root system of an experimental tomato plant, and the 32P activity in a leaf is measured 3.48 days later. By what factor must this reading be multiplied to correct for the decay that has occurred since the experiment began?arrow_forwardA beam of 5.0 MeV alpha particles (q-2e) has a cross-sectional area of 1.50 cm2. It is incident on flesh (p-950 kg/m³) and penetrates to a depth of 0.70 mm. a) What dose in Gy does the beam provide to the flesh in a time of 3.0 s? b) What effective dose does it provide? Assume the beam to carry a current of 2.50 x 109 A and to have QF - 14.arrow_forward
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