Introduction To Health Physics
5th Edition
ISBN: 9780071835275
Author: Johnson, Thomas E. (thomas Edward), Cember, Herman.
Publisher: Mcgraw-hill Education,
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Chapter 9, Problem 9.20P
To determine
The actual exposure rate.
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A radiographic technique calls for 46 kVp and 28 mAs which results in an exposure of 278 µGy. What is the expected exposure
if the technique is changed to 75 kVp and 14 mAs? Round your answer to the nearest whole number. Do not include units.
A beam of 5.0 MeV alpha particles (q-2e) has a cross-sectional area of 1.50 cm2. It is incident on flesh (p-950
kg/m³) and penetrates to a depth of 0.70 mm. a) What dose in Gy does the beam provide to the flesh in a time of
3.0 s? b) What effective dose does it provide? Assume the beam to carry a current of 2.50 x 109 A and to have QF
- 14.
✓
ON
"O
2.75 MeV
0.511 MeV
0.511 MeV
B, E= 1.73 MeV
Eave = 0.721 Mev
O MeV
Chapter 9 Solutions
Introduction To Health Physics
Ch. 9 - Prob. 9.1PCh. 9 - Prob. 9.2PCh. 9 - Prob. 9.3PCh. 9 - Prob. 9.4PCh. 9 - Prob. 9.5PCh. 9 - Prob. 9.6PCh. 9 - Prob. 9.7PCh. 9 - Prob. 9.8PCh. 9 - Prob. 9.9PCh. 9 - Prob. 9.10P
Ch. 9 - Prob. 9.11PCh. 9 - Prob. 9.12PCh. 9 - Prob. 9.13PCh. 9 - A counting system has a background of 360 counts...Ch. 9 - Prob. 9.15PCh. 9 - Prob. 9.16PCh. 9 - Prob. 9.17PCh. 9 - Prob. 9.18PCh. 9 - Prob. 9.19PCh. 9 - Prob. 9.20PCh. 9 - Prob. 9.21PCh. 9 - Prob. 9.22PCh. 9 - Prob. 9.23PCh. 9 - Prob. 9.24PCh. 9 - Prob. 9.25PCh. 9 - Prob. 9.26PCh. 9 - Prob. 9.27PCh. 9 - Prob. 9.28PCh. 9 - Prob. 9.29PCh. 9 - Prob. 9.31PCh. 9 - Prob. 9.33PCh. 9 - Prob. 9.34PCh. 9 - Prob. 9.35PCh. 9 - Prob. 9.38PCh. 9 - Prob. 9.39PCh. 9 - Prob. 9.44P
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- A small 10-gram source of cobalt-60 is in a vacuum. (a) What is the activity of the cobalt-60source in Bq? (b) What is the actual gamma-ray flux in cm2-s-1 at a point of measurement500 cm from the source due to the cobalt-60 emitted gamma-rays? (c) If the backgroundgamma-ray flux in the vicinity of the 10-g source is 7.8×107cm-2-s-1, what is the totalgamma-ray flux at the point of measurement, including the background? (d) What thicknessof a lead shield in cm would have to be placed between the source and the point ofmeasurement to reduce the total of the background plus the uncollided gamma-ray flux fromthe cobalt-60 source to 1.00×108cm-2-s-1 at that point? (I've attempted part a of the problem and don't know how to continue)arrow_forward4arrow_forwardquestion 4 pleasearrow_forward
- Question 1. There are four factors: A, B, C, D. We assume that each replicate was considered as a block. Fill in the table as below and analyze the experiment with conclusions. Using a = 0.05. Treatment combination Rep 1 Rep 2 7.786 | 7.377014 6.789 | 6.398278 5.834 5.554411 A C D -1 a - b 2.341 2.28354 6.133 5.702366 3.669 | 3.608621 d ab ас 6.154 5.87312 ad 5.819| 5.550515 bc 12.887 12.62869 2.753 2.261361 4.451 4.411148 0.873 | 0.793026 4.678 | 4.259536 3.728 3.695787 bd cd abc abd bcd аcd 10.478 10.33168 abcd 1.722 | 1.365419 Table 1arrow_forwardCalculate the dose in Sv to the chest of a patient given anx-ray under the following conditions. The x-ray beam intensityis 1.50 W/m2 , the area of the chest exposed is0.0750 m2 , 35.0% of the x-rays are absorbed in 20.0 kg oftissue, and the exposure time is 0.250 s.arrow_forward29. A shielded vial with a 0.1-mm thick lead shield contains 11. This A. 8 mR/hr B. 1 mR/hr shielded sample yields an exposure rate of 0.25 mR/hr at a distance of 3 cm. What will the exposure rate be at the same distance when the shield is removed? (The lead HVL for 125I is C. 0.5 mR/hr D. 0.25 mR/hr 0.02 mm.) 30. A shielded vial with a 4.0-mm thick lead shield contains "F. This shielded sample yields an exposure rate of 6 mR/hr at a distance of 1 cm. What will the exposure rate be at the same distance when the shield is removed? (The lead HVL for F is 4.0 mm.) A. 12 mR/hr B. 6 mR/hr C. 3 mR/hr D. 1.5 mR/hrarrow_forward
- 1. Consider the following data from the analysis of mercury using cold vapor atomic absorption spectrometry: Concentration (ppm) 10.0 1.00 0.000 No. of replicate 15 15 20 measurements Mean of S 9.95 1.15 0.0124 Standard deviation of 0.12 0.030 0.0075 the measurement, s The calibration data yielded the following equation: S= 1.09CHE + 0.298 Where CHg is the concentration in ppm of Hg and S is the relative intensity of the emission line of Hg. Calculate for the following: a. Calibration sensitivity b. Analytical sensitivity at 10.0 and 1.00 ppm of Hg; and С. Detection limitarrow_forward(a) A student wishes to measure the half-life of a radioactive substance using a small sample. Consecutive clicks of her radiation counter are randomly spaced in time. The counter registers 372 counts during one 5.00-min interval and 337 counts during the next 5.00 min. The average background rate is 15 counts per minute. Find the most probable value for the half-life. (b) Express the estimated half-life with an appropriate estimated uncertainty.arrow_forwardThe intensity of radiation at 2m was 300 mR/hr. What would the exposure be at 4m? Oa. 1200 mR/hr Ob. 600 mR/hr c. 75 mR/hr C. Od. 150 mR/hrarrow_forward
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