Introduction To Health Physics
Introduction To Health Physics
5th Edition
ISBN: 9780071835275
Author: Johnson, Thomas E. (thomas Edward), Cember, Herman.
Publisher: Mcgraw-hill Education,
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Chapter 9, Problem 9.25P
To determine

The charging voltage

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sq 4. Maximum surface resistance. Consider a square sheet of side L, thickness d, and electrical resistivity p. The resistance measured between opposite edges of the sheet is called the surface resistance: R = pL/ Ld = p/d, which is independent of the area of the sheet. (R is called the resistance per square and is expected in ohms per square, because p/d has the dimensions of ohms.) If we express p by p=m/ne²t, then Rq=m/ndet. Suppose now that the minimum value of the collision time is determined by scattering from surfaces of the sheet, so that Td/v, where v is the Fermi velocity. Thus the maximum surface resistivity is Rmvp/nd²e². Show for a monatomic metal sheet one atom thickness that sq Rħ/e² = 4.1k, where lkn is 10³ ohms. sq
In the last column in the data table, it says that it's about voltage(v) divided by current(A) is equal to ohms so V/A = ohms. So if it's V/A and if you divide them to get the slope it's (y2-y1)/(x2-x1) then shouldn't V be the y value and A be the x value? And can you also try to use a line of best bit instead of drawing the line through each dot?
A solid conductor has a conductor area of 2,774 kcmils, what is the diameter of this conductor in inches: Correct Answer: 3.331 + 0.01
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