(a) Interpretation: The alkyl halide and alkene required to produce derivative of cyclopropane are to be predicted. Concept introduction: Alkenes on reaction with alkyl halide in the presence of a strong base give derivative of cyclopropane. The C = C bond of alkene breaks and a single three membered cyclic ring is formed. Methylene ( :CH 2 ) is formed as a reactive intermediate during this reaction.

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Answer 1

Question

Chapter 9, Problem 9.35P

Interpretation Introduction

(a)

Interpretation:

The alkyl halide and alkene required to produce derivative of cyclopropane are to be predicted.

Concept introduction:

Alkenes on reaction with alkyl halide in the presence of a strong base give derivative of cyclopropane. The C=C bond of alkene breaks and a single three membered cyclic ring is formed. Methylene (:CH2) is formed as a reactive intermediate during this reaction.

Interpretation Introduction

(b)

Interpretation:

The alkyl halide and alkene required to produce derivative of cyclopropane are to be predicted.

Concept introduction:

Alkenes on reaction with alkyl halide in the presence of a strong base give derivative of cyclopropane. The C=C bond of alkene breaks and a single three membered cyclic ring is formed. Methylene (:CH2) is formed as a reactive intermediate during this reaction.

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Answer 2

Question

Chapter 9, Problem 9.35P

Interpretation Introduction

(a)

Interpretation:

The alkyl halide and alkene required to produce derivative of cyclopropane are to be predicted.

Concept introduction:

Alkenes on reaction with alkyl halide in the presence of a strong base give derivative of cyclopropane. The C=C bond of alkene breaks and a single three membered cyclic ring is formed. Methylene (:CH2) is formed as a reactive intermediate during this reaction.

Interpretation Introduction

(b)

Interpretation:

The alkyl halide and alkene required to produce derivative of cyclopropane are to be predicted.

Concept introduction:

Alkenes on reaction with alkyl halide in the presence of a strong base give derivative of cyclopropane. The C=C bond of alkene breaks and a single three membered cyclic ring is formed. Methylene (:CH2) is formed as a reactive intermediate during this reaction.

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Answer 3

Question

Chapter 9, Problem 9.35P

Interpretation Introduction

(a)

Interpretation:

The alkyl halide and alkene required to produce derivative of cyclopropane are to be predicted.

Concept introduction:

Alkenes on reaction with alkyl halide in the presence of a strong base give derivative of cyclopropane. The C=C bond of alkene breaks and a single three membered cyclic ring is formed. Methylene (:CH2) is formed as a reactive intermediate during this reaction.

Interpretation Introduction

(b)

Interpretation:

The alkyl halide and alkene required to produce derivative of cyclopropane are to be predicted.

Concept introduction:

Alkenes on reaction with alkyl halide in the presence of a strong base give derivative of cyclopropane. The C=C bond of alkene breaks and a single three membered cyclic ring is formed. Methylene (:CH2) is formed as a reactive intermediate during this reaction.

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Answer 4

Question

Chapter 9, Problem 9.35P

Interpretation Introduction

(a)

Interpretation:

The alkyl halide and alkene required to produce derivative of cyclopropane are to be predicted.

Concept introduction:

Alkenes on reaction with alkyl halide in the presence of a strong base give derivative of cyclopropane. The C=C bond of alkene breaks and a single three membered cyclic ring is formed. Methylene (:CH2) is formed as a reactive intermediate during this reaction.

Interpretation Introduction

(b)

Interpretation:

The alkyl halide and alkene required to produce derivative of cyclopropane are to be predicted.

Concept introduction:

Alkenes on reaction with alkyl halide in the presence of a strong base give derivative of cyclopropane. The C=C bond of alkene breaks and a single three membered cyclic ring is formed. Methylene (:CH2) is formed as a reactive intermediate during this reaction.

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Answer 5

Chapter 9, Problem 9.35P

Interpretation Introduction

(a)

Interpretation:

The alkyl halide and alkene required to produce derivative of cyclopropane are to be predicted.

Concept introduction:

Alkenes on reaction with alkyl halide in the presence of a strong base give derivative of cyclopropane. The C=C bond of alkene breaks and a single three membered cyclic ring is formed. Methylene (:CH2) is formed as a reactive intermediate during this reaction.

Interpretation Introduction

(b)

Interpretation:

The alkyl halide and alkene required to produce derivative of cyclopropane are to be predicted.

Concept introduction:

Alkenes on reaction with alkyl halide in the presence of a strong base give derivative of cyclopropane. The C=C bond of alkene breaks and a single three membered cyclic ring is formed. Methylene (:CH2) is formed as a reactive intermediate during this reaction.

Answer 6

Chapter 9, Problem 9.35P

Interpretation Introduction

(a)

Interpretation:

The alkyl halide and alkene required to produce derivative of cyclopropane are to be predicted.

Concept introduction:

Alkenes on reaction with alkyl halide in the presence of a strong base give derivative of cyclopropane. The C=C bond of alkene breaks and a single three membered cyclic ring is formed. Methylene (:CH2) is formed as a reactive intermediate during this reaction.

Answer 7

Chapter 9, Problem 9.35P

Interpretation Introduction

(a)

Interpretation:

The alkyl halide and alkene required to produce derivative of cyclopropane are to be predicted.

Concept introduction:

Alkenes on reaction with alkyl halide in the presence of a strong base give derivative of cyclopropane. The C=C bond of alkene breaks and a single three membered cyclic ring is formed. Methylene (:CH2) is formed as a reactive intermediate during this reaction.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The alkyl halide and alkene required to produce derivative of cyclopropane are to be predicted.

Concept introduction:

Alkenes on reaction with alkyl halide in the presence of a strong base give derivative of cyclopropane. The C=C bond of alkene breaks and a single three membered cyclic ring is formed. Methylene (:CH2) is formed as a reactive intermediate during this reaction.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The alkyl halide and alkene required to produce derivative of cyclopropane are to be predicted.

Concept introduction:

Alkenes on reaction with alkyl halide in the presence of a strong base give derivative of cyclopropane. The C=C bond of alkene breaks and a single three membered cyclic ring is formed. Methylene (:CH2) is formed as a reactive intermediate during this reaction.

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 9 - Prob. 9.1P Ch. 9 - Prob. 9.2P Ch. 9 - Prob. 9.3P Ch. 9 - Prob. 9.4P Ch. 9 - Prob. 9.5P Ch. 9 - Prob. 9.6P Ch. 9 - Prob. 9.7P Ch. 9 - Prob. 9.8P Ch. 9 - Prob. 9.9P Ch. 9 - Prob. 9.10P

Solution Summary: The author explains that the alkyl halide and alkene required to produce derivative of cyclopropane are shown in Figure 1.

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Chapter 9 Solutions