Chapter 9, Problem 9.155QP

(a)

Interpretation Introduction

Interpretation:

The balanced equation for the reaction of ${\text{KO}}_{\text{2}}$ with ${\text{CO}}_{\text{2}}$ should be written and oxidation number of Oxygen in ${\text{O}}_{\text{2}}{}^{\text{2-}}$ should be given and required volume of respired air reacts with $\text{7}\text{.00 g}$ ${\text{KO}}_{\text{2}}$ should be calculated.

Concept introduction:

Balanced equation:

Balanced equation is equation for a chemical reaction, which is written by the number of atoms for each element and total charges of ions are equal in the reaction for in both reactants and the products sides.

Oxidation number:

The oxidation number of an atom is varied by involving in reaction is called redox reaction.

In the redox reaction the number of electron is loosed or gained by an atom to form an electrically neutral product is called oxidation number.

Molarity:

The concentration of the solutions is given by the term of molarity and it is given by ratio between numbers of moles of solute present in litter of solution.

$\text{Molarity}\text{=}\frac{\text{No}\text{.mole}}{\text{volume}\text{(L)}}$

Mole:

The mole of the solute is calculated by multiplication of concentration of solution and volume of the solution and it is,

$\text{Mole}\text{=}\text{Concentration}\text{(M)×}\text{volume}\text{(L)}$

(b)

Interpretation Introduction

Interpretation:

The balanced equation for the reaction of ${\text{KO}}_{\text{2}}$ with ${\text{CO}}_{\text{2}}$ should be written and oxidation number of Oxygen in ${\text{O}}_{\text{2}}{}^{\text{2-}}$ should be given and required volume of respired air reacts with $\text{7}\text{.00 g}$ ${\text{KO}}_{\text{2}}$ should be calculated.

Concept introduction:

Balanced equation:

Balanced equation is equation for a chemical reaction, which is written by the number of atoms for each element and total charges of ions are equal in the reaction for in both reactants and the products sides.

Oxidation number:

The oxidation number of an atom is varied by involving in reaction is called redox reaction.

In the redox reaction the number of electron is loosed or gained by an atom to form an electrically neutral product is called oxidation number.

Molarity:

The concentration of the solutions is given by the term of molarity and it is given by ratio between numbers of moles of solute present in litter of solution.

$\text{Molarity}\text{=}\frac{\text{No}\text{.mole}}{\text{volume}\text{(L)}}$

Mole:

The mole of the solute is calculated by multiplication of concentration of solution and volume of the solution and it is,

$\text{Mole}\text{=}\text{Concentration}\text{(M)×}\text{volume}\text{(L)}$

(c)

Interpretation Introduction

Interpretation:

The balanced equation for the reaction of ${\text{KO}}_{\text{2}}$ with ${\text{CO}}_{\text{2}}$ should be written and oxidation number of Oxygen in ${\text{O}}_{\text{2}}{}^{\text{2-}}$ should be given and required volume of respired air reacts with $\text{7}\text{.00 g}$ ${\text{KO}}_{\text{2}}$ should be calculated.

Concept introduction:

Balanced equation:

Balanced equation is equation for a chemical reaction, which is written by the number of atoms for each element and total charges of ions are equal in the reaction for in both reactants and the products sides.

Oxidation number:

The oxidation number of an atom is varied by involving in reaction is called redox reaction.

In the redox reaction the number of electron is loosed or gained by an atom to form an electrically neutral product is called oxidation number.

Molarity:

The concentration of the solutions is given by the term of molarity and it is given by ratio between numbers of moles of solute present in litter of solution.

$\text{Molarity}\text{=}\frac{\text{No}\text{.mole}}{\text{volume}\text{(L)}}$

Mole:

The mole of the solute is calculated by multiplication of concentration of solution and volume of the solution and it is,

$\text{Mole}\text{=}\text{Concentration}\text{(M)×}\text{volume}\text{(L)}$