Chapter 9, Problem 9.150QP

Interpretation Introduction

Interpretation:

The mass percent of $\text{NaBr}$ in given ${\text{CaBr}}_{\text{2}}$ and $\text{NaBr}$ mixture should be calculated.

Concept introduction:

Precipitation reaction:

If precipitate is formed, when two soluble salt solutions are mixed together is known as precipitation reaction.

The mass of the precipitate is depends on the reactant masses.

Molarity:

The concentration of the solutions is given by the term of molarity and it is given by ratio between numbers of moles of solute present in litter of solution.

$\text{Molarity}\text{=}\frac{\text{No}\text{.mole}}{\text{volume}\text{(L)}}$

Mole:

The mole of compound is given by the ratio between taken mass of the compound and molar mass of the compound.

$\text{Mole}\text{=}\frac{\text{Massof}\text{the}\text{compound}}{\text{Molar}\text{mass}\text{of}\text{the}\text{compound}}$

Mass percentage:

Mass percentage of given compound is calculated by the ration between the mass of the analyte and total mass of the compound.

$\text{Mass}\text{percent}\text{=}\frac{\text{Mass}}{\text{Total}\text{mass}}$